"Kent Johnson" <[EMAIL PROTECTED]> wrote
> No, a set is a sequence, you can convert it to a list directly:
> b = list(a)
But this is better than an LC obviously! :-)
Alan G
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listin
"Andy Cheesman" <[EMAIL PROTECTED]> wrote
> only way of interconversion a brute force method?
>
> i.e a = set([1, 2, 3])
> b = []
> for thing in a:
> b.append(thing)
Which looks a lot like a list comprehension:
b = [member for member in Set([1,2,3])]
HTH,
--
Alan Gauld
Author of the Learn to
Andy Cheesman wrote:
> I've googled a bit for manipulation of
> sets into other data structure(lists, arrays) and not seen much. Is the
> only way of interconversion a brute force method?
>
> i.e a = set([1, 2, 3])
> b = []
> for thing in a:
> b.append(thing)
No, a set
Thats a great solution, thanks! I've googled a bit for manipulation of
sets into other data structure(lists, arrays) and not seen much. Is the
only way of interconversion a brute force method?
i.e a = set([1, 2, 3])
b = []
for thing in a:
b.append(thing)
Andy
Eric Brunson wrote:
> Bob Gailer wrote:
>> Andy Cheesman wrote:
>>
>>> Hi people,
>>>
>>> If I've two numpy arrays, is there a non-looping way of finding common
>>> values. (the example below has identical shapes for the arrays but this
>>> may not be the case in my scenario)
>>>
>>> e.g
>>> a =
Bob Gailer wrote:
> Andy Cheesman wrote:
>
>> Hi people,
>>
>> If I've two numpy arrays, is there a non-looping way of finding common
>> values. (the example below has identical shapes for the arrays but this
>> may not be the case in my scenario)
>>
>> e.g
>> a = array([0, 1, 2, 3, 4, 5, 6, 7,
Andy Cheesman wrote:
> Hi people,
>
> If I've two numpy arrays, is there a non-looping way of finding common
> values. (the example below has identical shapes for the arrays but this
> may not be the case in my scenario)
>
> e.g
> a = array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
> b = array([ 5, 6, 7,
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Andy Cheesman
>
> Hi people,
>
> If I've two numpy arrays, is there a non-looping way of finding common
> values. (the example below has identical shapes for the
> arrays but this
> may not be the case in my scenario)
>
> e.g
>
Hi people,
If I've two numpy arrays, is there a non-looping way of finding common
values. (the example below has identical shapes for the arrays but this
may not be the case in my scenario)
e.g
a = array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
b = array([ 5, 6, 7, 8, 9, 10, 11, 12, 13, 14])
answer =
