On Sat, 7 Jul 2007, Alan Gauld wrote:
> I'm intrigued as to why people are using weird combinations
> of math to manipulate bitstrings given that Python has a full
> set of bitwise operators. Surely it is easier and more obvious
> to simply shift the bits right or left using >> and << and use
> bi
Well, I contacted the programmer of these controls and the reason they
mask the MSB on these reports is to designate what type of sensor it
is. If the MSB is set, the sensor is one type, if not, another. So,
knowing that i could put these together ok. To me, the speed is of no
consequence like it w
"Kent Johnson" <[EMAIL PROTECTED]> wrote
>> to simply shift the bits right or left using >> and << and use
>> bitwise and/or operations than do all this multiplication and
>> addition malarky. (Its also a lot faster!)
>
> Are you sure about that? With Python 2.5 on a MacBook Pro it seems
> to
>
Alan Gauld wrote:
> Surely it is easier and more obvious
> to simply shift the bits right or left using >> and << and use
> bitwise and/or operations than do all this multiplication and
> addition malarky. (Its also a lot faster!)
Are you sure about that? With Python 2.5 on a MacBook Pro it seems
"Terry Carroll" <[EMAIL PROTECTED]> wrote
>> In your formula ( (176 & 127) * 256 + 192 ) you're only using 7
>> bits
>> of your high byte. Why are you masking off that last bit?
>
> Scrounging through some old code, I used to use this to pull out the
> length:
>
> def ID3TagLength(s):
>
On Fri, 6 Jul 2007, Jerry Hill wrote:
> In your formula ( (176 & 127) * 256 + 192 ) you're only using 7 bits
> of your high byte. Why are you masking off that last bit?
I know in MP3 files, some of the ID3 lengths are coded this way, i.e. as a
four-byte field, each byte of which has the high-o
On 7/6/07, shawn bright <[EMAIL PROTECTED]> wrote:
> i have a number 12480
> i have a low byte of 192 and a high byte of 176
Maybe I'm being dense, but that doesn't make any sense at all to me.
The high byte of 12480 is 48, and the low byte is 192, isn't it?
Because (48 * 256) + 192 = 12480?
In y
hello all,
i have a number 12480
i have a low byte of 192 and a high byte of 176
so i can do this
IDLE 1.2.1 No Subprocess
>>> (176 & 127) * 256 + 192
12480
but if i start with the 12480, how do i get the two bytes (lo and hi)
that make it up?
i kinda know what i am doing here,
