On Fri, Sep 05, 2014 at 05:32:34PM -0400, Crush wrote:
> Ok nevermind, I did not figure it out. My code...
You say "Never mind", which normally means the problem is solved, but
then you say it doesn't do what you want. So do you want help or not?
:-)
> count = 0
> while count < 3:
> count
On 05/09/14 23:11, Alan Gauld wrote:
Let's translate that to Python
count = 1
error = subprocess.Popen('command') # execute once
oops, that should be subprocess.call()
sorry.
while error and count < 3: # if error and less than 3
error = subprocess.call('command') # on succ
On 05/09/14 22:32, Crush wrote:
count = 0
while count < 3:
count += 1
Subprocess.Popen('command')
This is not real code since 'command' is presumably
not the real command and subprocess is not spelled with an 'S'...
Its usually better to post real code.
if count == 3:
sys.exit
On Fri, Sep 5, 2014 at 2:32 PM, Crush wrote:
> Ok nevermind, I did not figure it out. My code...
>
> count = 0
> while count < 3:
> count += 1
> Subprocess.Popen('command')
> if count == 3:
> sys.exit()
>
> This does not work as I want it to; it consecutively executes the command
> t
On 05Sep2014 17:32, Crush wrote:
Ok nevermind, I did not figure it out. My code...
count = 0
while count < 3:
count += 1
Subprocess.Popen('command')
if count == 3:
sys.exit()
This does not work as I want it to; it consecutively executes the command
three times in a row. I only want
Ok nevermind, I did not figure it out. My code...
count = 0
while count < 3:
count += 1
Subprocess.Popen('command')
if count == 3:
sys.exit()
This does not work as I want it to; it consecutively executes the command
three times in a row. I only want it to execute once. However, if t
