Chris,
I was just fooling around and I wanted to do something for myself before
going to bed the other night.
func myflatten will turn say [ 34 [90] [12] 1] into [34 90 12 1].
Just like its name sounds.
Emeka
On Fri, Aug 12, 2011 at 7:03 PM, Christopher King wrote:
> try:
>> it
>
> try:
> iter(item) # test for iterability
> if len(item) == 1 and item == item[0]:
> gut.append(item)
> else:
> gut = gut + flatten(item)
>
> except TypeError:
> gut.append(item)
>
I wouldn't put the what you want to do i
On 08/12/2011 05:31 AM, ALAN GAULD wrote:
It'll work on lists and tuples, for simple examples. But beware that
when you iterate through strings, the individual characters are also
strings, and this function will fail with an error like:
RuntimeError: maximum recursion depth exceeded
Oh,
> It'll work on lists and tuples, for simple examples. But beware that
> when you iterate through strings, the individual characters are also
> strings, and this function will fail with an error like:
>RuntimeError: maximum recursion depth exceeded
Oh, good catch Dave.
So you'd want to a
On 08/12/2011 03:47 AM, Alan Gauld wrote:
On 12/08/11 07:04, Emeka wrote:
Hello All,
I need help here, type(item) == [].__class__:. What is the idiomatic way
of doing it?
if type(item) == type([])...
or in this case
if type(item) == list...
But probably preferrable to using type is to use
On 12/08/11 07:04, Emeka wrote:
Hello All,
I need help here, type(item) == [].__class__:. What is the idiomatic way
of doing it?
if type(item) == type([])...
or in this case
if type(item) == list...
But probably preferrable to using type is to use isinstance:
if isinstance(item, list)...
Hello All,
I need help here, type(item) == [].__class__:. What is the idiomatic way of
doing it?
def myflatten(my_data):
gut = []
for item in my_data:
if type(item) == [].__class__:
gut = gut + myflatten ( item)
else:
gut.append(item)
return gut
print myfl
