On 04/17/2013 08:12 PM, Alan Gauld wrote:
On 17/04/13 20:27, Danilo Chilene wrote:
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
pr
On 17/04/13 20:27, Danilo Chilene wrote:
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
print c
I run python file.py a and returns t
On 17/04/2013 20:27, Danilo Chilene wrote:
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
On 04/17/2013 05:15 PM, Danny Yoo wrote:
Yup! Sorry about my tone for its stridency. But I just got concerned
that the original poster seemed content about turning the chain of if
statements into a table definition. To my mind, they're very closely
related, data and control. I'm trying to pus
Yup! Sorry about my tone for its stridency. But I just got concerned
that the original poster seemed content about turning the chain of if
statements into a table definition. To my mind, they're very closely
related, data and control. I'm trying to push the OP to realizing
that if they are doin
On 04/17/2013 04:49 PM, Danny Yoo wrote:
Wait. If the solution that we're stopping at to use a hashtable here,
that's not quite right.
Nothing wrong with a dict, if a proper specification of the problem were
available. Notice that in my solution, the messages were not all
trivially related
Wait. If the solution that we're stopping at to use a hashtable here,
that's not quite right. A good solution to this should be _much_
shorter, on the order of a one-liner. Hashtables are great, but
they're not the answer to everything.
If we're doing something like:
a -> "This is A"
b
Hello Dave,
1) I'm using Python 2.7
2) The program wasn't suppose to really work, was just a example.
3) You assumed correct.
That's was what I looking for, worked like charm.
Thanks!
On Wed, Apr 17, 2013 at 5:18 PM, Dave Angel wrote:
> On 04/17/2013 03:27 PM, Danilo Chilene wrote:
>
>> Dear
On Wed, Apr 17, 2013 at 1:03 PM, Danny Yoo wrote:
> ##
> ## double: string -> string
> def double(x):
> return x + x
>
>
> ## For example, a blast from the past:
> print "The Noid says: " + double("pizza")
> ##
>
I'm sorry, but this is a bug.
On 04/17/2013 03:27 PM, Danilo Chilene wrote:
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c
What's the part that's "changing"? What's the part that stays the same?
I would recommend thinking of this in terms of a function.
Can you write a function that consumes a letter l and returns the
string "This is ..." where "..." is the uppercased l?
As an example of a simple function on string
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
print c
I run python file.py a and return
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