On 11/21/2010 8:15 AM Josep M. Fontana said...
return sorted(word_table.items(), key=lambda item: item[1], reverse=True)
What I don't understand is the syntax of "item : item[1]".
Key defines a lambda function that accepts as a single passed parameter
named item and returns the element i
> it is difficult for me not to be profuse in my thanks because you guys really
> go beyond the call of duty. I love this list. The responses in this list most
> of the times don't just address the problem at hand but are also useful in a
> more
general sense and help people become better progra
Martin, Alan, col speed and everybody that helped: I think I'm going
to stop because I'm repeating myself but it is difficult for me not to
be profuse in my thanks because you guys really go beyond the call of
duty. I love this list. The responses in this list most of the times
don't just address t
--> snip
>However, even with countWords2, which is supposed to overcome this
>problem, it feels as if I've entered an infinite loop.
>Josep M.
Just my twopenneth, I'm a noob and I'm not going to try such a big file on
my old machine, but:
1. Maybe create a *set* from the wordlist, loop through
"Martin A. Brown" wrote
* Somebody will be certain to point out a language or languages
that provide some sort of facility to abstract the use of
multiple processors without the explicit use of threads.
ISTR Occam did that?
Occam being the purpose designed language for the transputer,
Good evening,
: It turns out that matters of efficiency appear to be VERY
: important in this case. The example in my message was a very
: short string but the file that I'm trying to process is pretty
: big (20MB of text).
Efficiency is best addressed first and foremost, not by hardware,
If the file is big use Peter's method, but 45 minutes still seems
very long so it may be theres a hidden bug in there somehwew.
However...
> When I look at the current processes running on my computer, I see the
> Python process taking 100% of the CPU. Since my computer has a
> multi-core pr
Thanks Alan, Peter and Steve,
Instead of answering each one of you independently let me try to use
my response to Steve's message as the basis for an answer to all of
you.
It turns out that matters of efficiency appear to be VERY important in
this case. The example in my message was a very short
Josep M. Fontana wrote:
def countWords(a_list):
words = {}
for i in range(len(a_list)):
item = a_list[i]
count = a_list.count(item)
words[item] = count
return sorted(words.items(), key=lambda item: item[1], reverse=True)
with open('output.txt', 'a') as token_f
Hi,
I'm trying to do something that should be very simple. I want to
generate a list of the words that appear in a document according to
their frequencies. So, the list generated by the script should be
something like this:
the : 3
book: 2
was : 2
read: 1
by: 1
[...]
This would be obtained from
10 matches
Mail list logo
