"peter hodgson" <[EMAIL PROTECTED]> wrote
for key in b:
keylist = key.split(',')
if keylist < a:
i = a.index(keylist[0])
print a[:i] + [b[key]] + a[i+len(keylist):]
now, i get it, mostly; but keylist being shorter than the list "a"
keylist < a
True
This is not testin
greetings, fellow ventriloquists;
the exchanges on this list are great tutorials; sometimes i don't quite
get the finer points; like here:
On Mon, Jun 16, 2008 at 10:41 AM, GTXY20 <[EMAIL PROTECTED]> wrote:
> Let's say I have a list like the following:
>
> a = ['a1','a2','a3','a4','a5','a6']
>
On Mon, Jun 16, 2008 at 11:41:25AM -0400, GTXY20 wrote:
> Hello all,
>
> Thanks in advance for any thoughts, direction, and guidance.
>
> Let's say I have a list like the following:
>
> a = ['a1','a2','a3','a4','a5','a6']
>
> and then I have dictionary like the following:
>
> b = {'a1,a2,a3':'
On Mon, Jun 16, 2008 at 10:41 AM, GTXY20 <[EMAIL PROTECTED]> wrote:
> I need some direction and thoughts on how I might seach the list for the
> string (the key in dict b) sequence in list a and replace the occurance with
> the value from dict b. At the end I would like to have list a represented
>
Hello all,
Thanks in advance for any thoughts, direction, and guidance.
Let's say I have a list like the following:
a = ['a1','a2','a3','a4','a5','a6']
and then I have dictionary like the following:
b = {'a1,a2,a3':'super'}
I need some direction and thoughts on how I might seach the list for
