On 26/06/12 23:30, Alexander Quest wrote:
My question is how does Python know to return just the part in the
parentheses and not to return the "blahblah" and the "yattayattayatta",
etc...?
If you want to know *how* Python does it you will have to read the
module code (probably in C so downloa
I'm a bit confused about extracting data using re.search or re.findall.
Say I have the following code: tuples =
re.findall(r'blahblah(\d+)yattayattayatta(\w+)moreblahblahblah(\w+)over',
text)
So I'm looking for that string in 'text', and I intend to extract the parts
which have parentheses around
On Thu, 12 Apr 2012 09:06:53 -0700
Michael Lewis wrote:
> Here's the "pattern" portion that I don't understand:
>
> re.findall("[^A-Z]+[A-Z]{3}([a-z])[A-Z]{3}[^A-Z]+"
>
You have 5 different parts here:
1) [^A-Z]+ - this matches one or more non-uppercase characters.
The brackets [] describe a
On 12/04/12 15:47, Steven D'Aprano wrote:
Regular expressions are like super-charged wildcards. In the DOS or
Windows command.com or cmd.exe shell, you can use wildcards * and ? to
match any characters, or a single character. In Linux and Macintosh
shells, you have the same thing only even more
>
> mjole...@gmail.com wrote:
> > Hi everyone,
> >
> > I am having trouble understanding re.findall(). I've read through the
> > documentation and looked at at some examples online, but I still don't
> have
> > a clear picture.
> >
> > I am going through pythonchallenge.com and I am on challenge 3.
On 12/04/2012 14:53, mjole...@gmail.com wrote:
Hi everyone,
I am having trouble understanding re.findall(). I've read through the
documentation and looked at at some examples online, but I still don't have a
clear picture.
I am going through pythonchallenge.com and I am on challenge 3. I've s
mjole...@gmail.com wrote:
Hi everyone,
I am having trouble understanding re.findall(). I've read through the
documentation and looked at at some examples online, but I still don't have
a clear picture.
I am going through pythonchallenge.com and I am on challenge 3. I've see.
The answer to the p
Hi everyone,
I am having trouble understanding re.findall(). I've read through the
documentation and looked at at some examples online, but I still don't have a
clear picture.
I am going through pythonchallenge.com and I am on challenge 3. I've see. The
answer to the problem, but I don't unde
On Tue, Sep 14, 2010 at 01:09:21PM -0400, Michael Scharf wrote:
> Thank you. I should have figured "groups" were the paren groups. I see it
> clearly now. And your solution will work for the larger thing I'm trying to
> do --- thanks.
> And yes: I know this matches some non-date-like dates, b
Hi Evert,
Thank you. I should have figured "groups" were the paren groups. I see it
clearly now. And your solution will work for the larger thing I'm trying to
do --- thanks.
And yes: I know this matches some non-date-like dates, but the data is such
that it should work out ok.
Thanks again,
> I have a regex that matches dates in various formats. I've tested the regex
> in a reliable testbed, and it seems to match what I want (dates in formats
> like "1 Jan 2010" and "January 1, 2010" and also "January 2008"). It's just
> that using re.findall with it is giving me weird output. I
Hi all,
I have a regex that matches dates in various formats. I've tested the regex
in a reliable testbed, and it seems to match what I want (dates in formats
like "1 Jan 2010" and "January 1, 2010" and also "January 2008"). It's just
that using re.findall with it is giving me weird output. I'm
> I may put in an enhancement request to change the name of re.findall to
> re.findsome.
Hi Terry,
A typical use of regular expressions is to break text into a sequence of
non-overlapping tokens. There's nothing that technically stops us from
applying the theory of regular expressions to get o
On Sat, 3 Sep 2005, Kent Johnson wrote:
> But I would say your chances of getting the name changed are slim to
> none, the Python developers are extremely reluctant to make changes that
> break existing code.
Yeah, I know. I was mostly joking.
Mostly.
__
Terry Carroll wrote:
> On Sat, 3 Sep 2005, Kent Johnson wrote:
>
>
>>AFAIK that is the way to do it.
>
>
> I may put in an enhancement request to change the name of re.findall to
> re.findsome.
Or maybe findnonoverlapping. But I would say your chances of getting the name
changed are slim to
On Sat, 3 Sep 2005, Kent Johnson wrote:
> AFAIK that is the way to do it.
I may put in an enhancement request to change the name of re.findall to
re.findsome.
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Terry Carroll wrote:
> But he asked me, is there a standard method to get even overlapped
> strings?
>
> After looking through the docs, I couldn't find a way to do this in
> standard methods, so I gave him a quick RYO solution:
>
>
def myfindall(regex, seq):
>
> ...resultlist=[]
> ...
A friend of mine got bitten by an expectations bug. he was using
re.findall to look for all occurances of strings matching a pattern, and a
substring he *knew* was in there did not pop out.
the bug was that it overlapped another matching substring, and findall
only returns non-overlapping str
Sheesh. Star wars/programming humour. Better not be any Star Trek
humour, that'll go over my head even further.
On Tue, 15 Mar 2005 22:24:53 +, Max Noel <[EMAIL PROTECTED]> wrote:
>
> On Mar 15, 2005, at 21:59, Liam Clarke wrote:
>
> > On Tue, 15 Mar 2005 17:09:50 +, Max Noel <[EMAIL PR
On Mar 15, 2005, at 21:59, Liam Clarke wrote:
On Tue, 15 Mar 2005 17:09:50 +, Max Noel <[EMAIL PROTECTED]>
wrote:
re.findall returns a list object (as the error message says).
Use name
= x[1] instead. (and be careful, numbering starts from 0, so this code
may contain a Kenobi error)
Liam Clarke wrote:
On Tue, 15 Mar 2005 17:09:50 +, Max Noel <[EMAIL PROTECTED]> wrote:
re.findall returns a list object (as the error message says). Use name
= x[1] instead. (and be careful, numbering starts from 0, so this code
may contain a Kenobi error).
Kenobi as in Obi Wan?
or may
On Tue, 15 Mar 2005 17:09:50 +, Max Noel <[EMAIL PROTECTED]> wrote:
>
> re.findall returns a list object (as the error message says). Use name
> = x[1] instead. (and be careful, numbering starts from 0, so this code
> may contain a Kenobi error).
>
Kenobi as in Obi Wan?
--
'Ther
On Mar 15, 2005, at 17:41, Ron Nixon wrote:
Max:
Thanks that seem to do the trick. One question though,
how do you write a tuple out as a list to a new file
like the example I have in my code
Ron
You mean, all the members of the list, separated by commas, with a new
line at the end? Well, this ma
Kent:
The code is below. Here's the error message.
Traceback (most recent call last):
File "C:/Python24/reformat.py", line 5, in
-toplevel-
name = x.group(1)
AttributeError: 'list' object has no attribute 'group'
import re
f = open('reformat.txt').read()
pat = re.compile(r"([^\r\n]+)\n
On Mar 15, 2005, at 16:44, Ron Nixon wrote:
Kent:
The code is below. Here's the error message.
Traceback (most recent call last):
File "C:/Python24/reformat.py", line 5, in
-toplevel-
name = x.group(1)
AttributeError: 'list' object has no attribute 'group'
re.findall returns a list object (a
Ron Nixon wrote:
Thanks to all who replied to my post earlier on re's.
I'm still preplexed by why re.search and re.match
works in the code below, but not re.findall.
re.findall is suppose to return all non-voerlapping
occurances of the pattern that matches in this
example, but it returns errors. L
Thanks to all who replied to my post earlier on re's.
I'm still preplexed by why re.search and re.match
works in the code below, but not re.findall.
re.findall is suppose to return all non-voerlapping
occurances of the pattern that matches in this
example, but it returns errors. Looking through th
27 matches
Mail list logo
