w chun wrote:
>>- ->: \d+/?\d*
>>- ->
>>- ->ie 1 or more digits followed by 0 or 1 slashes followed by 0 or more
>>digits.
>
>
>
> this looks like it'll also accept invalid data, such as "1/" ... i
> think there's some more tweaking involved to get it so that if there's
> a '/', there is at lea
> - ->: \d+/?\d*
> - ->
> - ->ie 1 or more digits followed by 0 or 1 slashes followed by 0 or more
> digits.
this looks like it'll also accept invalid data, such as "1/" ... i
think there's some more tweaking involved to get it so that if there's
a '/', there is at least one digit afterwards.
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Today (Oct 27, 2005) at 9:29am, Ed Singleton spoke these wise words:
- ->OR tests for the truth of the first thing then the truth of the second.
- ->
- ->The first part of your OR is always true, so it doesn't test the second.
- ->
- ->What you reall
OR tests for the truth of the first thing then the truth of the second.
The first part of your OR is always true, so it doesn't test the second.
What you really want to do is look for a digit and then look for more
digits or a slash and some more digits.
So:
: \d(\d+|/\d+)
but this is easier b
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os - Slackware
py - 2.4.1
I'm trying to grab the value 10 in
Visibility: 10 mile(s):0
but sometimes the value looks like
Visibility: 1/2 mile(s):0
My not working regex looks like
re.compile(': \d+|: \d/\d')
If I'm understanding right, this shou