cimjls wrote:
>
> number = int(raw_input("Please enter a number between
> 1 and 10: "))
> if number < 1:
> print "That is an incorrect number. Please try
> again."
> raw_input("Please enter a number between 1 and 10:
> ")
> if number > 10:
> print "That is an incorrect numb
> if number > 10:
> print "That is an incorrect number. Please try
> again."
Maybe you could do better if you check for all valid numbers first, and
finally if no valid number has been entered, then print an error
message, instead of checking for all possibilities of error. Hint: check
that
cimjls wrote:
> Here is what I need to do:
>
> Create an IF branching statement that will take the
> users input from 1-10 and return the English word for
> the number. (1 is One, 2 is Two, etc.) If the user
> enters a value outside of the range of 1-10, display
> an error message, and ask the u
> How do I get it to work after an incorrect number is
> entered? I am stuck on this and would appreciate and
> help or suggestions?
Use exception
>>> try:
... int("hoge")
... except(ValueError):
... print('incorrect')
...
incorrect
> elif number == 1:
> print "One"
> elif number == 2:
Here is what I need to do:
Create an IF branching statement that will take the
users input from 1-10 and return the English word for
the number. (1 is One, 2 is Two, etc.) If the user
enters a value outside of the range of 1-10, display
an error message, and ask the user to enter a valid
selecti
