Hoffmann wrote:
> We are almost there. I changed the code and, at least,
> I got the correct output. However, I also got a
> traceback. I didn't understand the traceback. Could
> you clarify that?
> Thanks,
> Hoffmann
> ps: The new code:
>
>
vehicle='car'
index = -1 #index of the last le
> Hi John,
>
> We are almost there. I changed the code and, at least,
> I got the correct output. However, I also got a
> traceback. I didn't understand the traceback. Could
> you clarify that?
> Thanks,
> Hoffmann
> ps: The new code:
>
> >>> vehicle='car'
> >>> index = -1 #index of the last lette
--- Adam <[EMAIL PROTECTED]> wrote:
> I just wanted to throw in a couple of ideas for you
> on this subject.
> These are the ways I would personally think of going
> about this
> problem:
>
> >>> ''.join([s[n] for n in range(len(s)-1, -1, -1)])
> 'rac'
> Which looks a bit fugly but is nice and sh
I just wanted to throw in a couple of ideas for you on this subject.
These are the ways I would personally think of going about this
problem:
>>> ''.join([s[n] for n in range(len(s)-1, -1, -1)])
'rac'
Which looks a bit fugly but is nice and short if you can manage list comps.
and now my favourite
--- John Fouhy <[EMAIL PROTECTED]> wrote:
> On 29/03/06, Hoffmann <[EMAIL PROTECTED]> wrote:
> > Hi John,
> >
> > (1) vehicle[index] is: 'c'
> > (2) If index = index = 1, so vehicle[index]
> becomes:
> > 'a'
>
> What I'm getting at here is that, by changing index,
> we can change
> which letter w
