On Fri, Aug 29, 2014 at 2:17 PM, Derek Jenkins wrote:
> Hi everybody,
>
> I have a list that I want to go through and finally print a total
> count of particular items. In this case, I want to print the result of
> how many A's and B's are in the list.
>
> honor_roll_count = 0
> student_grades = [
On 29/08/14 20:17, Derek Jenkins wrote:
Hi everybody,
I have a list that I want to go through and finally print a total
count of particular items. In this case, I want to print the result of
how many A's and B's are in the list.
honor_roll_count = 0
student_grades = ["A", "C", "B", "B", "C", "A
Alex,
Thanks for taking this one step further! I do appreciate it... +1
On Fri, Aug 29, 2014 at 3:48 PM, Alex Kleider wrote:
> On 2014-08-29 12:17, Derek Jenkins wrote:
>>
>> Hi everybody,
>>
>> I have a list that I want to go through and finally print a total
>> count of particular items. In th
honor_roll_count = 0
student_grades = ["A", "C", "B", "B", "C", "A", "F", "B", "B", "B", "C", "A"]
for grades in student_grades:
if grades == "A" or grades == "B":
honor_roll_count = honor_roll_count + 1
print honor_roll_count
That works more to my liking. Thanks a million, Danny an
>
> The above code prints 8 lines, each being an entry for which item in
> the list was either A or B. Again, I'm looking for the result to be
> the number 8 itself - the total number of instances that A or B occurs
> in the list.
Hi Derek,
Hint: the code currently prints a variable within the l
Hi everybody,
I have a list that I want to go through and finally print a total
count of particular items. In this case, I want to print the result of
how many A's and B's are in the list.
honor_roll_count = 0
student_grades = ["A", "C", "B", "B", "C", "A", "F", "B", "B", "B", "C", "A"]
for grad
