"Kent Johnson" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
On Wed, Jun 18, 2008 at 8:30 PM, Keith Troell <[EMAIL PROTECTED]> wrote:
Let's say I have a list of lists l == [[1, 2, 3], [2, 3, 1], [3, 2, 1],
[1,
3, 2]]
If I do a l.sort(), it sorts on the first element of each lis
On Wed, Jun 18, 2008 at 10:48 PM, Forrest Y. Yu <[EMAIL PROTECTED]> wrote:
> I know, it's NOT beautiful code, but it seems work. If you have no better
> way, try this:
>
> """Sort on the second elements."""
> def xchg12(l) :
> for m in l:
> m[0], m[1] = m[1], m[0]
>
> l = [[1, 2, 3], [2
>
> Message: 8
> Date: Wed, 18 Jun 2008 19:30:05 -0500
> From: Keith Troell <[EMAIL PROTECTED]>
> Subject: [Tutor] Newbie: Sorting lists of lists
> To: tutor@python.org
> Message-ID: <[EMAIL PROTECTED]>
> Content-Type: text/plain; charset=US-ASCII; delsp=yes;
On Wed, Jun 18, 2008 at 8:30 PM, Keith Troell <[EMAIL PROTECTED]> wrote:
> Let's say I have a list of lists l == [[1, 2, 3], [2, 3, 1], [3, 2, 1], [1,
> 3, 2]]
>
> If I do a l.sort(), it sorts on the first element of each listed list:
>
l.sort()
l
> [[1, 2, 3], [1, 3, 2], [2, 3, 1], [3, 2
On 19/06/2008, Keith Troell <[EMAIL PROTECTED]> wrote:
> Let's say I have a list of lists l == [[1, 2, 3], [2, 3, 1], [3, 2, 1], [1,
> 3, 2]]
>
> If I do a l.sort(), it sorts on the first element of each listed list:
>
> >>> l.sort()
> >>> l
> [[1, 2, 3], [1, 3, 2], [2, 3, 1], [3, 2, 1]]
>
>
>
Let's say I have a list of lists l == [[1, 2, 3], [2, 3, 1], [3, 2,
1], [1, 3, 2]]
If I do a l.sort(), it sorts on the first element of each listed list:
>>> l.sort()
>>> l
[[1, 2, 3], [1, 3, 2], [2, 3, 1], [3, 2, 1]]
How can I sort on the second or third elements of the listed lists?
Keith
