Andreas Kostyrka wrote:
> With 2.5 you can even do stuff like that:
>
x=[range(5), range(3), range(7)]
max(x, key=lambda i: len(i))
> [0, 1, 2, 3, 4, 5, 6]
No need for the lambda, just use
max(x, key=len)
Kent
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Thanks,
but I am restricted to using 2.3.4 for now, so
longest = max([len(x) for x in ll])
works for me
On 12/28/06, Andreas Kostyrka <[EMAIL PROTECTED]> wrote:
* Python <[EMAIL PROTECTED]> [061228 20:44]:
> On Thu, 2006-12-28 at 11:27 -0800, Tony Cappellini wrote:
> >
> >
> > I want to use
* Python <[EMAIL PROTECTED]> [061228 20:44]:
> On Thu, 2006-12-28 at 11:27 -0800, Tony Cappellini wrote:
> >
> >
> > I want to use a list comp to get the length of the longest string in a
> > list, but can't quite get the syntax right.
> >
> > l1=['abc', 'abcde', 'abcfdtea']
> >
> > longest=0
>
On Thu, 2006-12-28 at 11:27 -0800, Tony Cappellini wrote:
>
>
> I want to use a list comp to get the length of the longest string in a
> list, but can't quite get the syntax right.
>
> l1=['abc', 'abcde', 'abcfdtea']
>
> longest=0
> [x for x in l1 if len(x) > longest]
Use max to get the longe
I want to use a list comp to get the length of the longest string in a list,
but can't quite get the syntax right.
l1=['abc', 'abcde', 'abcfdtea']
longest=0
[x for x in l1 if len(x) > longest]
The problem is I can't add the true clause to the if statement in a list
comp as in
if len(x) > longes
