An additional suggestion:
> =
> # Add your functions below!
> def average(numbers):
> total = sum(numbers)
> total = total / len(numbers)
> return total
Don't re-assign total here. The problem is that conceptually "total" no
longer represents the total in the second assignment.
Thanks Alan.
Removed that .
=
# Add your functions below!
def average(numbers):
total = sum(numbers)
total = total / len(numbers)
return total
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(stude
On 22/10/15 10:03, Vusa Moyo wrote:
Hi Guys. Thanks for the responses and assistance.
I came right after-all. The last 2 blocks read the following.
Glad you are happy but there is still something you could improve:
def get_class_average(students):
results = []
for a in students:
Hi Guys. Thanks for the responses and assistance.
I came right after-all. The last 2 blocks read the following.
def get_class_average(students):
results = []
for a in students:
b = float(get_average(a))
results.append(b)
return average(results)
students = [lloyd, al
On 20/10/15 12:29, Vusa Moyo wrote:
Hi there. My script is as follows,
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
# Add your function below!
def average(numbers):
>total = sum(numbers)
>
Hi Vusa, and welcome.
On Tue, Oct 20, 2015 at 01:29:59PM +0200, Vusa Moyo wrote:
> Hi there. My script is as follows,
[...]
> def get_class_average(students):
> results = []
> for a in students:
> b = int(get_average(a))
> results.append([b])
> return results
I'
Hi there. My script is as follows,
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.
