On 7/5/2010 4:19 PM Alan Gauld said...
But for the specific case of file extensions the os.path.splitext() is
a better solution.
If, as the names suggest, the source is the file system, then I'd reach
for glob.
Emile
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Tutor maillist - Tu
On Mon, 05 Jul 2010 20:29:02 +0200
tutor-requ...@python.org wrote:
> Date: Mon, 5 Jul 2010 13:54:55 -0400
> From: Vineeth Rakesh
> To: tutor@python.org
> Subject: [Tutor] Help return a pattern from list
> Message-ID:
>
> Content-Type: text/plain; charset="
"Shashwat Anand" wrote
list =
["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
[i for i in list if i[-4:] == '.mp3']
['something1.mp3', 'something2.mp3']
Or even easier:
[s for s in list if s.endswith('.mp3')]
But for the specific case of file extensions the os.pa
On Mon, Jul 5, 2010 at 11:58 PM, Shashwat Anand wrote:
>
>
> On Mon, Jul 5, 2010 at 11:24 PM, Vineeth Rakesh
> wrote:
>
>> Hello all,
>>
>> Can some one help me to return a special pattern from a list.
>>
>> say list =
>> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
>>
>
On Mon, Jul 5, 2010 at 11:24 PM, Vineeth Rakesh wrote:
> Hello all,
>
> Can some one help me to return a special pattern from a list.
>
> say list =
> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
>
One suggestion. Don't name a list as list. Use l or List or any other
vari
On 5 July 2010 19:54, Vineeth Rakesh wrote:
> Can some one help me to return a special pattern from a list.
>
> say list =
> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
>
> now say I just need to return the files with .mp3 extension. How to go about
> doing this?
Use os.
Hello all,
Can some one help me to return a special pattern from a list.
say list =
["something1.mp3","something2.mp3","something4.pdf","something5.odt"]
now say I just need to return the files with .mp3 extension. How to go about
doing this?
Thanks
Vin
_
