Gerhardus Geldenhuis wrote:
try:
server = xmlrpclib.Server("http://192.168.2.11/cobbler_api";)
#...
except xmlrpclib.Fault as detail:
print 'xmlrpc error'
print detail
#print detail.arguments
print repr(detail)
I don't understand what I am getting from the exception
On Mon, Nov 7, 2011 at 12:52 PM, Gerhardus Geldenhuis
wrote:
> Hi
> I am trying to handle exceptions for a xmlrpc class interfacing with
> cobbler.
> The exception:
> xmlrpclib.Fault: test_profile'">
>
> and the experimental code.
> try:
> server = xmlrpclib.Server("http://192.168.2.11/cob
Hi
I am trying to handle exceptions for a xmlrpc class interfacing with
cobbler.
The exception:
xmlrpclib.Fault:
and the experimental code.
try:
server = xmlrpclib.Server("http://192.168.2.11/cobbler_api";)
#...
except xmlrpclib.Fault as detail:
print 'xmlrpc error'
prin