Re: [Tutor] HANDLING ERRORS

2005-06-30 Thread Alan G
> numbers = {} > menu_choice = 0 > print_menu() > while menu_choice != 5: > > try: > > menu_choice = input("Type in a number (1-5):") > if menu_choice == 1: > print "Telephone Numbers:" > > except ValueError: > print "Oops! That was n

Re: [Tutor] HANDLING ERRORS

2005-06-30 Thread Light
HI Move the "except ..." outside the "if...". Try this one: print "Type Control C or -1 to exit" def print_menu(): print '1. Print Phone Numbers' print '2. Add a Phone Number' print '3. Remove a Phone Number' print '4. Lookup a Phone Number' print '5. Quit' print numbers =

[Tutor] HANDLING ERRORS

2005-06-30 Thread Feziwe Mpondo
HI help mi. here's what i tried but it's not working print "Type Control C or -1 to exit" def print_menu(): print '1. Print Phone Numbers' print '2. Add a Phone Number' print '3. Remove a Phone Number' print '4. Lookup a Phone Number' print '5. Quit' print numbers = {} menu