Premature optimization is the devil. Care not which method is faster. Only
optimize when the whole program is too slow and then find which area is the
biggest culprit and optimize that.
Computers are very very fast these days. Even embedded systems are so fast
you don't understand how fast they ar
>>> t = timeit.Timer( '1000%2')
>>> t.timeit(100)
0.25893402099609375
>>> t = timeit.Timer( '1000&1')
>>> t.timeit(100)
0.2567589282989502
It's almost insignificantly faster.
However as a programmer and a mathematician, I disagree with your
position that the bitwise operation is mo
On Wed, 19 Sep 2007, Boykie Mackay wrote:
> if not n&1:
> return false
>
> The above should return false for all even numbers,numbers being
> represented by n.I have tried to wrap my head around the 'not n&1' but
> I'm failing to understand what's going on.Could someone please explain
> the s
>
> > The above snippet is taking advantage of a similar property of binary
> > numbers, which are base 2. What the above snippet is doing is checking
> to
> > see if that last digit is a 0 or not (asking "not n&1" is equivalent to
> > asking "n&0", since that digit can only be a 0 or 1).
>
> Not q
Thanks.
The analogy to the decimal system was a big help in getting me to
understand the principle.
On Wed, 2007-09-19 at 09:47 -0400, taserian wrote:
> On 9/19/07, Boykie Mackay <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> I have come across a bit of code to find if a group
Hi Boyks,
Boykie Mackay wrote:
> Hi guys,
>
> I have come across a bit of code to find if a group of numbers is odd or
> even.The code snippet is shown below:
>
> if not n&1:
> return false
>
> The above should return false for all even numbers,numbers being
> represented by n.I have tried
On 9/19/07, Boykie Mackay <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> I have come across a bit of code to find if a group of numbers is odd or
> even.The code snippet is shown below:
>
> if not n&1:
> return false
>
> The above should return false for all even numbers,numbers being
> represented
On 9/19/07, Boykie Mackay <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> I have come across a bit of code to find if a group of numbers is odd or
> even.The code snippet is shown below:
>
> if not n&1:
>return false
>
> The above should return false for all even numbers,numbers being
> represented
Hi guys,
I have come across a bit of code to find if a group of numbers is odd or
even.The code snippet is shown below:
if not n&1:
return false
The above should return false for all even numbers,numbers being
represented by n.I have tried to wrap my head around the 'not n&1' but
I'm failing
