The dictionary of functions was the way to go and does perform much faster than
if/elif's. Thank-you!
- Original Message -
From: inhahe
To: Dinesh B Vadhia
Cc: tutor@python.org
Sent: Thursday, May 22, 2008 4:15 PM
Subject: Re: [Tutor] Equivalent 'case' statement
Hi,
I messed in earlier message, my apologies.
Message: 1
Date: Fri, 23 May 2008 00:25:23 +0100
From: "Alan Gauld" <[EMAIL PROTECTED]>
Subject: Re: [Tutor] Equivalent 'case' statement
To: tutor@python.org
Message-ID: <[EMAIL PROTECTED]>
Content-Type: text/plain;
"Dinesh B Vadhia" <[EMAIL PROTECTED]> wrote
Is there an equivalent to the C/C++ 'case' (or 'switch') statement
in Python?
No, just if/elif
However you can often achieve similar results with a dictionary:
def func1(v): return v
def func2(v): return v*2
switch = { 'val1': func1,
>
> cases = {
> 1: lambda: x*2
> 2: lambda: y**2
> 3: lambda: sys.stdout.write("hi\n")
> }
>
i forgot the commas.
cases = {
1: lambda: x*2,
2: lambda: y**2,
3: lambda: sys.stdout.write("hi\n")
}
>
> your functions and lambdas can also take parameters of course
>
lambda a, b: a*b
_
no, but you can
a) use elifs
if c==1:
do this
elif c==2:
do this
elif c==3:
do this
b) make a dictionary of functions (this is faster)
def case1: do this
def case2: do that
def case3: do the other
cases = {1: case2, 2: case2, 3:case3}
cases[c]()
if your functions are one expression you c
Is there an equivalent to the C/C++ 'case' (or 'switch') statement in Python?
Dinesh
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