On Tue, Oct 23, 2012 at 4:51 AM, Walter Prins wrote:
>
> Looking at the email source it clearly shows as being mimetype
> "multipart" with both a plaintext and HTML part. I don't think you
> can much criticise GMail for interpreting and attempting to render an
> HTML email as HTML. The biggest c
On 23/10/12 19:51, Walter Prins wrote:
It's an HTML post.
Not according to the version of Thunderbird I am using, which shows it
as a plain text email.
I suspect that the HTML attachment may be invalid HTML, understandable
by Gmail and possibly nothing else. Typical of Google :(
Looking at t
>> It's an HTML post.
>
> Not according to the version of Thunderbird I am using, which shows it
> as a plain text email.
>
> I suspect that the HTML attachment may be invalid HTML, understandable
> by Gmail and possibly nothing else. Typical of Google :(
Looking at the email source it clearly sho
On 22/10/12 21:52, eryksun wrote:
On Mon, Oct 22, 2012 at 6:37 AM, Steven D'Aprano wrote:
On 22/10/12 21:21, Saad Javed wrote:
for x, y , z in zip(a, b, c):
L.extend([x, y, z])
print L
This is not your code, because that gives a SyntaxError. Where is
the indentation? Indentation is required
Hi Saad,
On 22 October 2012 11:37, Steven D'Aprano wrote:
> On 22/10/12 21:21, Saad Javed wrote:
>> I'm trying to create a list (L) from items of different lists (a, b, c)
>> but
>> in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc])
>> L = []
>> a = [1, 2, 3, 4]
>> b = ['a', 'b', 'c', '
On Mon, Oct 22, 2012 at 6:37 AM, Steven D'Aprano wrote:
> On 22/10/12 21:21, Saad Javed wrote:
>>
>> for x, y , z in zip(a, b, c):
>> L.extend([x, y, z])
>> print L
>
> This is not your code, because that gives a SyntaxError. Where is
> the indentation? Indentation is required in Python, if you le
On 22/10/12 21:21, Saad Javed wrote:
Hi,
I'm trying to create a list (L) from items of different lists (a, b, c) but
in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc])
L = []
a = [1, 2, 3, 4]
b = ['a', 'b', 'c', 'd']
c = [2009, 2010, 2011, 2012]
for x, y , z in zip(a, b, c):
L.extend(
Hi Saad,
On 22 October 2012 11:21, Saad Javed wrote:
> Hi,
>
> I'm trying to create a list (L) from items of different lists (a, b, c) but
> in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc])
> L = []
> a = [1, 2, 3, 4]
> b = ['a', 'b', 'c', 'd']
> c = [2009, 2010, 2011, 2012]
>
> for x
Hi,
I'm trying to create a list (L) from items of different lists (a, b, c) but
in a specific order (L = [[a1, b1, c1], [a2, b2, c2]...etc])
L = []
a = [1, 2, 3, 4]
b = ['a', 'b', 'c', 'd']
c = [2009, 2010, 2011, 2012]
for x, y , z in zip(a, b, c):
L.extend([x, y, z])
print L
But this outputs:
[
