Please do not top post.
> Sorry for the double-post.
>
> I don't think I am wrong either. Replace doesn't return a list of words in
> the way that my code sample was setup to do.
> How would you solve it with replace? Maybe an example prove the point
> better.
>
> -Mario
> On Wed, Jun 20, 2012 a
Sorry for the double-post.
I don't think I am wrong either. Replace doesn't return a list of words in
the way that my code sample was setup to do.
How would you solve it with replace? Maybe an example prove the point
better.
-Mario
On Wed, Jun 20, 2012 at 4:10 PM, mariocatch wrote:
> Yes, I me
Yes, I meant split(). Was a typo :)
On Wed, Jun 20, 2012 at 3:56 PM, Prasad, Ramit wrote:
> Please always post back to the list.
>
> > Nope, strip() was intended so we get a list back instead of a string.
> Need
> > the list for iteration down below that.
>
> >> >para = paragraph.strip('.').s
Please always post back to the list.
> Nope, strip() was intended so we get a list back instead of a string. Need
> the list for iteration down below that.
>> >para = paragraph.strip('.').strip(',').strip().split()
>> I think you want replace not strip.
>>
>> See http://docs.python.org/libra
Oğuzhan Öğreden wrote:
Hi,
I have been learning Python and trying little bits of coding for a while.
Recently I tried to have a paragraph and create a list of its words, then
counting those words. Here is the code:
[code snipped]
I can't understand your code! Indentation is messed up badly. I
> para = paragraph.strip('.').strip(',').strip().split()
I think you want replace not strip.
See http://docs.python.org/library/stdtypes.html#string-methods
Ramit
Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216
Here's one way, can surely be optimized:
*paragraph = "This paragraph contains words once, more than once, and
possibly not at all either. Figure that one out. "
para = paragraph.strip('.').strip(',').strip().split()
wordDict = {}
for word in para:
word = word.strip('.').st
On 20/06/12 16:20, Martin A. Brown wrote:
: should have written something like "counting how many times each
: word occured" insted of "counting words".
You might like to try out collections.defaultdict().
Even a standard dict would simplify the code dramatically.
The defaultdict does sui
Hello,
: Sorry, it seems like I was not clear enough in that statement. I
: should have written something like "counting how many times each
: word occured" insted of "counting words".
You might like to try out collections.defaultdict().
import collections
summary = collections.defaul
I think this is more of what you ar looking for:
>>> a = 'this is a list with is repeated twice.'
>>> a
'this is a list with is repeated twice.'
>>> alist = a.strip().split()
>>> alist
['this', 'is', 'a', 'list', 'with', 'is', 'repeated', 'twice.']
>>> var='is'
>>> alist.count(var)
2
>>>
On Wed,
Sorry, it seems like I was not clear enough in that statement. I should
have written something like "counting how many times each word occured"
insted of "counting words".
2012/6/20 mariocatch
> Hello,
>
> Not sure if this is what you're trying to solve, although it sounds like
> it based on you
Hello,
Not sure if this is what you're trying to solve, although it sounds like it
based on your leading statement.
I think what you have is more complicated than it needs to be for something
that simple:
Why not something like this?
*paragraph = """I have been learning Python and trying litt
Hi,
I have been learning Python and trying little bits of coding for a while.
Recently I tried to have a paragraph and create a list of its words, then
counting those words. Here is the code:
import re
>
>
>> a = """Performs the template substitution, returning a new string.
>> mapping is any di
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