> I'm tryin compare a string with a value with style of
pattern-matching.
>
> string = 'i686'
>
> if string == glob.glob(i?86):
Use regular expressions and turn it around:
import re
s = 'i686'
ex = re.compile('i?86')
if ex.match(s): print 'they match!'
Is that what you mean?
Alan G.
_
Quoting Jonas Melian <[EMAIL PROTECTED]>:
> I'm tryin compare a string with a value with style of pattern-matching.
>
> string = 'i686'
>
> if string == glob.glob(i?86):
This is a task for regular expressions!
Have a look at the re module.
(and feel free to ask for more help if you're having
I'm tryin compare a string with a value with style of pattern-matching.
string = 'i686'
if string == glob.glob(i?86):
This is fails because glob() is for listing files in a directory that
match a Unix ls-pattern
how make it?
Thanks!
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Tutor maillis
