> Basically it's not evaluating it the way you think it is:
>
>Your first example really equates to:
>
> if (1 or 5) in rollList:
Not quite, its doing:
if 1 or 5 in rollList:
We can demonstrate that with:
>>> if 1 or 0 in [6,2,3]: print 'True'
...
True
>>> if (1or 0) in [6,2,3]: print 'True'
..
Jason Massey wrote:
> John,
>
> Basically it's not evaluating it the way you think it is:
Right.
>
> Your first example really equates to:
>
> if (1 or 5) in rollList:
>etc...
>
> (1 or 5) equals 1 and 1 isn't in the your list.
Not quite. It's
if 1 or (5 in rollList):
Since 1 evaluat
John,Basically it's not evaluating it the way you think it is:Your first example really equates to:if (1 or 5) in rollList: etc...(1 or 5) equals 1 and 1 isn't in the your list.
On 4/26/06, John Connors <[EMAIL PROTECTED]> wrote:
G'day,I found something today that has me confused. I'm making a l
G'day,
I found something today that has me confused. I'm making a list of 6 random
dice rolls and I want to check if any 1's or 5's were rolled. I tried this
way first and it returns true even if there are no 1's or 5's. I'll use a
roll of all 2's as an example.
rollList = [2,2,2,2,2,2]
if 1
