I don't know what "sufficient numbers" means, but perhaps it's "significant
digits" that was intended. And you have to decide if you want ten digits to the right of the
decimal point, or ten significant digits in the whole number. That determines whether you want to
round decnum2 or the final
Le Sun, 29 Mar 2009 22:42:43 -0500,
Chris Castillo s'exprima ainsi:
> myinput = raw_input("Please enter a binary real number: ")
> myinput = myinput.split(".")
>
> binstr1 = myinput[0]
> binstr2 = myinput[1]
>
> decnum1 = 0
> decnum2 = 0
>
> for i in binstr1:
> decnum1 = decnum1 * 2 + int
2009/3/30 Chris Castillo :
> yeah that function would help but how would I join both sides again to get a
> decimal real(float) to round?
>
> for example myfloat = decnum1, ".", decnum2 doesn't work because the string
> "." isn't a valid int type. how would I join those to be a float again?
The ea
yeah that function would help but how would I join both sides again to get a
decimal real(float) to round?
for example myfloat = decnum1, ".", decnum2 doesn't work because the string
"." isn't a valid int type. how would I join those to be a float again?
On Sun, Mar 29, 2009 at 10:46 PM, John Fou
2009/3/30 Chris Castillo :
> that is what I have so far but I need to create a condition where I need
> only 10 sufficient numbers from the variable decnum2. I know I need
> something like
> if len(decnum2) > 11:
> decnum2 = decnum2[0:11]
Perhaps the round() function will help?
>>> round(1234
myinput = raw_input("Please enter a binary real number: ")
myinput = myinput.split(".")
binstr1 = myinput[0]
binstr2 = myinput[1]
decnum1 = 0
decnum2 = 0
for i in binstr1:
decnum1 = decnum1 * 2 + int(i)
for k in binstr2:
decnum2 = decnum2 * 2 + int(k)
print "\nThe binary real number
