On Sun, Dec 9, 2012 at 4:48 AM, Peter Otten <__pete...@web.de> wrote:
>
def interleave(items, separator):
> ... for item in items:
> ... yield item
> ... yield separator
> ...
+1 for this solution if a generator function is desired. It only
requires basic Python sy
Mike wrote:
> Hello everyone,
>
> I was wondering if someone could show me a better way to achieve what
> I am trying to do. Here is my test code:
>
> d=[]
> c="00"
> a="A,B,C,D"
> b=a.split(',')
> for item in b:
> d.append(item)
> d.append(c)
> print tup
On Sat, Dec 8, 2012 at 7:18 PM, Steven D'Aprano wrote:
>
> from itertools import izip_longest
> def longmux(*iterables, **kwargs):
> # This is much easier in Python 3.
For comparison, here it is in 3.x with fillvalue as a keyword-only argument:
from itertools import zip_longest
def
On 09/12/12 10:45, Mike wrote:
Thank you. Works well.
Actually, no, it doesn't work well. You only think it works well because
you've only tested it with tiny amounts of data.
On Sat, Dec 8, 2012 at 4:18 PM, bob gailer wrote:
tuple(sum([list(x) for x in zip(a,[c]*len(a))],[]))
If you t
On 09/12/12 06:39, Mike wrote:
Hello everyone,
I was wondering if someone could show me a better way to achieve what
I am trying to do. Here is my test code:
d=[]
c="00"
a="A,B,C,D"
b=a.split(',')
for item in b:
d.append(item)
d.append(c)
print t
Thank you. Works well.
Mike
On Sat, Dec 8, 2012 at 4:18 PM, bob gailer wrote:
> tuple(sum([list(x) for x in zip(a,[c]*len(a))],[]))
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On 12/8/2012 2:39 PM, Mike wrote:
Hello everyone,
I was wondering if someone could show me a better way to achieve what
I am trying to do. Here is my test code:
d=[]
c="00"
a="A,B,C,D"
b=a.split(',')
for item in b:
d.append(item)
d.append(c)
prin
Hello everyone,
I was wondering if someone could show me a better way to achieve what
I am trying to do. Here is my test code:
d=[]
c="00"
a="A,B,C,D"
b=a.split(',')
for item in b:
d.append(item)
d.append(c)
print tuple(d)
Basically what I want to end up
