On 28/02/07, Smith, Jeff <[EMAIL PROTECTED]> wrote:
> I realize however that this is probably much less efficient since you
> are iterating over the inner list rather than just taking it on in
> whole.
Well, you know what they say --- don't guess, profile :-)
Morpork:~ repton$ python -m timeit -s
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of John Fouhy
Sent: Monday, February 26, 2007 4:00 PM
To: Smith, Jeff
Cc: tutor@python.org
Subject: Re: [Tutor] Another list comprehension question
On 27/02/07, Smith, Jeff <[EMAIL PROTECTED]> wrote:
-Original Message-
From: Bob Gailer [mailto:[EMAIL PROTECTED]
Sent: Monday, February 26, 2007 3:53 PM
To: Smith, Jeff
Cc: tutor@python.org
Subject: Re: [Tutor] Another list comprehension question
>> files = list()
>Or just files = []
I tend to prefer the former since it h
John Fouhy wrote:
[snip]
>
> Or [x for k in get_clists() for x in get_clist(k)] using your original
> structure.
>
Well I learned something!
--
Bob Gailer
510-978-4454
___
Tutor maillist - Tutor@python.org
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Hi Jeff,
On 27/02/07, Smith, Jeff <[EMAIL PROTECTED]> wrote:
> I'm probably missing something simple here but is there anyway to
> accomplish the following with a list comprehension?
>
> def get_clists():
> return [1, 2, 3]
>
> def get_clist(num):
> if num == 1:
> return ['a', 'b',
Smith, Jeff wrote:
> I'm probably missing something simple here but is there anyway to
> accomplish the following with a list comprehension?
>
Each element created by a comprehension corresponds to an element
returned by the for (if) clause. So we have to find a way for the for
clause to retur
I'm probably missing something simple here but is there anyway to
accomplish the following with a list comprehension?
def get_clists():
return [1, 2, 3]
def get_clist(num):
if num == 1:
return ['a', 'b', 'c']
if num == 2:
return ['x', 'y', 'z']
if num == 3:
