As Wolfram pointed out, os.path.splitext() is a good way to do this. It is also more robust than the
other solutions because it does the right thing if there is no extension on the original file name.
I just want to say that your first solution can be written much more simply as
x=a[:a.rfind('.')
Hi all,
I'm writing some code, and I want to take a given path + filename, and
change the file extension to *.bak.
In doing so, (entirely internal this function), I am assuming -
That the file will always have an extension
Thathe extension will vary
But, it will follow the general DOS format of
