Quoting Lolo Lolo :
Hi, can i ask why the name ~/my_venv/ .. is that just to indicate ~
as the home directory?
The name was just an example. Yes, '~' is your home directory. You can
actually use this in your shell
instead of typing the whole path.
You probably want to put virtual enviro
Quoting "Tobias M." :
Quoting Lolo Lolo :
Hi Tobias can i just ask. As i already have Python 3.3, when i
install this separate version of 3.3, will there be a conflict on
the command line when i type python3.3? This install i want just
for virtualenvs but i wonder if it would
Quoting Lolo Lolo :
Hi Tobias can i just ask. As i already have Python 3.3, when i
install this separate version of 3.3, will there be a conflict on
the command line when i type python3.3? This install i want just for
virtualenvs but i wonder if it would replace my other 3.3 as the
defa
On 24.12.2013 20:15, Lolo Lolo wrote:
ive struggled all day to install pip on ubuntu 12.04 for python 3.3 .
The only pip in the apt-get cache is for python 2. i tried to download
pip from source but setuptools is missing when it tries to import it.
This made me download setuptools with apt-get
On 22.12.2013 16:59, Tobias M. wrote:
On 12/22/2013 04:50 PM, Mark Lawrence wrote:
I'm sorry that I can't help directly, but the asyncio module is so
new that I don't know if any of the other regulars here can help
either :( I'd be inclined to wait for 24 hours from tim
On 12/22/2013 04:50 PM, Mark Lawrence wrote:
I'm sorry that I can't help directly, but the asyncio module is so new
that I don't know if any of the other regulars here can help either :(
I'd be inclined to wait for 24 hours from time of posting and if you
don't get any positive responses, the
Hello,
I am currently writing an event-driven client library for a network
protocol [1] and chose to use the new asyncio module. I have no
experience with asynchronous IO and don't understand all the concepts in
asyncio yet. So I'm not sure if asyncio is actually the right choice .
My goal:
Hi Reuben,
Yes, I think the logging module is the best way to do it.
And it's pretty easy, see this minimal example:
import logging
logging.basicConfig(filename="foo.log", level=logging.DEBUG)
logging.debug("This is a log message")
The log levels are a great way, to control how much will be lo
Peter Otten wrote:
You are right; the misunderstanding is that I wasn't advertising the above
"fancy" solution (which is buggy, btw).
Yes, I wasn't sure about the irony in you last post ;)
Peter Otten wrote:
I have now implemented what I had in mind with the protocol to function name
mapping,
Am 10.01.2013 15:15, schrieb Peter Otten:
Of course handle_1_42() is not exactly the method name one would hope for.
You could, again, strive for simplicity and add a lookup table that maps
protocol tuples to function /names/ , but as simplicity doesn't seem to be
your cup of tea:
class Handlers
Dave Angel wrote:
But as it's the simplest solution, and one with no runtime overhead, you
really should consider it. Having a line or two following the class
definition is not uncommon in Python, and comments can make sure the
reader of the code understands it's part of the class initialization
Tobias M. wrote:
Well I think this is an elegant solution.
But due to my protocol a packet type is uniquely defined by a
combination of two header fields (that contain integers). Building a
verbose method name from these would complicate it again.
EDIT: I actually meant "meaningful m
Am 10.01.2013 13:48, schrieb Peter Otten:
If you adopt this approach you might omit the lookup dictionary and use
getattr():
... @classmethod
... def handle_foo(cls): print "Hello from B.handle_foo()"
... @classmethod
... def get_handler(cls, packet_type):
... return
Am 10.01.2013 13:57, schrieb eryksun:
That should be
cls.method_list[0].__get__(None, cls)()
The way you have it binds the method to type(MyClass), which in this
case is "type" itself. See cm_descr_get in funcobject.c, CPython 2.7
(line 645):
http://hg.python.org/cpython/file/70274d53c1dd
Steven D'Aprano wrote:
To answer your direct question, all you need to do is manually imitate
what
Python does when you call a descriptor (see below):
py> MyClass.method_list[0].__get__(MyClass, None)()
Hello World
So, inside the foo() method, do this:
@classmethod
def foo(cls):
Peter Otten wrote:
Build the list outside the class: MyClass.method_list = [MyClass.bar]
Thanks, that is a solution. But I don't really like to put the list
outside the class as it is strongly related to the class and not used
outside.
Hugo Arts wrote:
What piece of your code requires this li
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