Thanks for your help. That makes a lot more sense.
Not to ask too many stupid questions, but why does the L2 assignment in the
if-block create a new L variable? Shouldn't the scope from the function
definition dominate the inner scope of the if-block?
Thanks,
Josh
> Josh,
>
> If you print t
Hi all,
I was going through the tutorial at http://docs.python.org/tut/node6.html when I
came to the bit about default arguments with this code:
def f(a, L=[]):
L.append(a)
return L
print f(1)
print f(2)
print f(3)
returns:
[1]
[1, 2]
[1, 2, 3]
>From the postings here, I think I underst
