> Why did you change file mode to "a"?
I was trying different things and forgot to change it back before I cut/pasted.
>
>
> dest_path = os.path.dirname(fullpath)
> x.extractall(dest_path)
>
Ding ding ding, winner winner chicken dinner!
It's working!
Final .py stand alone code is:
import os, os.
>> Near as I can tell, I got rid of the permissions error, the ZipFile
>> error with the missing capital 'F'
>> Now I need to 'get into' the non zipped folder of each student and
>> unzip any and all zips that are inside of it.
>
>
> The error message says 'No such file or directory'. That means th
> No but Python did when it ran your code and it tried to tell you. The trick
> is to read the error message, see what line of code it occurs at and then
> look very closely at that line of code and the surrounding lines of code.
> The first thing to check for is a typo.
To be honest, I did check
>
> Capital F. ZipFile not Zipfile.
>
Keyboard - Forehead - SCHMACK.
(and hand/forehead smack.)
DOH!
Thank you.
Greg
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>> but now get a " x = zipfile.Zipfile(item,'r')
>> AttributeError: 'module' object has no attribute 'Zipfile' "
>>
>> error
>>
>> gr, this is going to send me to the funny farm!
>>
>> greg
>>
> One way to avoid the "funny farm" is to learn to use the tools that
> Python provides, built-in.
>
> but a better way to do that is:
> if item.endswith('.zip')
>
>> x = zipfile.Zipfile(item,'r')
>> x.extractall()
>> x.close()
>>
ok, I used that (above)
typed below:
for item in zipContents:
if item.endswith('.zip'):
x = zipfile.Zipfile(item,'r')
x.ex
>>> > You're trying to open the directory as if it were a zipfile. You should
>>> > pass in the path to a zipfile not to a folder.
>>>
>>> Agreed, but how do I do that "pass in the path to a zipfile'?
>>> Using an if statement I presume?
>>>
>>> > >
>>>
>>> > > I guess my first issue is to resolve
> >
> > z.close
>
> You need to have round brackets to actually call the close method, i.e.:
>
> z.close()
>
Fixed
> >
> >
> > It works, I get the following in the Python Shell:
> >
> > '>>> RESTART
> > =
>
> You need to add the folder where python.exe is to your PATH variable.
I just realized the path we're heading down here isn't going to work.
I need on .py file to be up an running so that I can add it to my tool
in ArcGIS.
>
> Oscar
I appreciate the help Oscar, and I believe it would work th
>
> You need to add the folder where python.exe is to your PATH variable.
>
> First you need to find the folder where python is on your computer. You can
> do this from within a python script using the following two lines:
> import sys
> print sys.executable
>
> Once you've found the folder contain
On Wed, Sep 19, 2012 at 10:40 AM, Peter Otten <__pete...@web.de> wrote:
> Steven D'Aprano wrote:
>
>> That's what we're here for! Don't be shy about asking questions.
>
> Indeed. Also, Gregory, don't expect anything to work directly. Programming
> is mostly an iterative process where you write just
>>> and then run it from the shell like this:
On Wed, Sep 19, 2012 at 10:20 AM, Peter Otten <__pete...@web.de> wrote:
> Gregory Lund wrote:
>>> and then run it from the shell like this:
ahh, windows shell, not python shell.
from the directions Peter linked to, I shift-
more info:
> Consider it done, i have a new .py file saved as 'unzip_twice.py'
but it would be easier (the whole purpose of this task) is to have a
stand alone script that would work without having to open up the
shell.
In ArcGIS, I call the script by double clicking on my tool, selecting
the .zi
> Using Peter's code, if you create a plain text file called "unzip_twice.py"
> containing:
>
>
> import glob
> import os
> import sys
> import zipfile
>
> source_file = sys.argv[1]
> dest_folder = sys.argv[2]
>
> zipfile.ZipFile(source_file).extractall(dest_folder)
>
> inner_zips_pattern = os.path
>
> Your lack of response in the previous thread
>
> http://mail.python.org/pipermail/tutor/2012-August/090742.html
>
> is not a big motivation to answer this one.
I didn't have any response to post, I got the basics to work using a
hint from a colleague in and was able to grade the assignment, ho
I teach at a college and I'm trying to use Python (2.6 because I'm
running my tool in ArcGIS) to unzip a .zip file that contains one
folder full of student folders, each with 1 or more submissions
(zipfiles) that represent student submissions to weekly lab
assignments.
It all starts with an origin
# neophyte .py/pyTutor user.
# I am also a university GIS lecturer. My students submit their lab
assignments (zipped up into one zipfile) to a depository, which I
download as a single zip containing all 40 students' zipfiles.
# Goal: unzip a zipfile of student zipfiles and then unzip each
students'
Only my second try to post to this list.
This is a dumb question with a simple (I presume) solution...
but...
how do I take a txt file with semicolon separated values and create a
dictionary and a list?
( in 2.6 because I'm working with ArcGIS.)
text file is as follows: (saved as text_data.txt) (i
I'm Not looking for an absolute solution, but perhaps some insight
into some snippets of code, or
suggestions of where I should seek out answers to this issue.
Or where I've gone wrong below.
NOTE: currently this 'code' below reads my file and writes a file, but
what it's doing in the middl
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