On 15/09/2015 23.14, Francesco A. Loffredo wrote:
On 14/09/2015 13:50, Oscar Benjamin wrote:
... Your algorithm loops through all triples and accepts any
triple if it doesn't immediately conflict with any of the
triples already accepted.
If you were solving a sud
On 14/09/2015 13:50, Oscar Benjamin wrote:
On 10 September 2015 at 08:45, Francesco Loffredo via Tutor
wrote:
I wrote a small routine (below) to check when and if my code and the formula
do match. It easily shows that
they only match for len(pool) == (2 ** N) - 1, with N greater or equal to 2.
