On Mar 21, 2015 1:22 AM, "Michael Omohundro"
wrote:
>
> Does anyone know how to create a python script to generate an aspect
raster from the input elevation in a digital elevation model?
>
This topic is out of the normal scope of the mailing list. It's hard to say
if you are having a python issue
On 31/03/2015 21:49, boB Stepp wrote:
On Tue, Mar 31, 2015 at 3:42 PM, Zachary Ware
wrote:
Also, not that since you aren't using the index for anything, you
don't need to use enumerate() to iterate over the list. Just do "for
item in L:". Of course, if you actually use the index in the real
Ian -
Note that if all your keys are named 'broadcast', the dictionary approach
is probably not going to work. You'll end up with something like:
{ 'broadcast': 'last_value_in_the_list' }
On Tue, Mar 31, 2015 at 10:56 AM, Ian D wrote:
> Ok Thanks a lot. And sadly not a typo, my bad logic ov
On Tue, Mar 31, 2015 at 3:42 PM, Zachary Ware
wrote:
> Also, not that since you aren't using the index for anything, you
> don't need to use enumerate() to iterate over the list. Just do "for
> item in L:". Of course, if you actually use the index in the real
> code that I assume this was cut o
On Tue, Mar 31, 2015 at 3:32 PM, Dave Angel wrote:
> On 03/31/2015 04:23 PM, boB Stepp wrote:
>>
>> The following behavior has me stumped:
>>
>> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
>> (Intel)] on win32
>> Type "copyright", "credits" or "license()" for more information.
On Tue, Mar 31, 2015 at 3:37 PM, boB Stepp wrote:
> On Tue, Mar 31, 2015 at 3:28 PM, Zachary Ware
> wrote:
>> On Tue, Mar 31, 2015 at 3:23 PM, boB Stepp wrote:
>>> The following behavior has me stumped:
>>>
>>> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
>>> (Intel)] on win3
On Tue, Mar 31, 2015 at 3:28 PM, Zachary Ware
wrote:
> On Tue, Mar 31, 2015 at 3:23 PM, boB Stepp wrote:
>> The following behavior has me stumped:
>>
>> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
>> (Intel)] on win32
>> Type "copyright", "credits" or "license()" for more inf
On 03/31/2015 04:23 PM, boB Stepp wrote:
The following behavior has me stumped:
Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
(Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
L = ['#ROI:roi_0', '#TXT:text_0', '#1:one^two^three']
for i, item i
On Tue, Mar 31, 2015 at 3:23 PM, boB Stepp wrote:
> The following behavior has me stumped:
>
> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
> (Intel)] on win32
> Type "copyright", "credits" or "license()" for more information.
L = ['#ROI:roi_0', '#TXT:text_0', '#1:one^two^
The following behavior has me stumped:
Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
(Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> L = ['#ROI:roi_0', '#TXT:text_0', '#1:one^two^three']
>>> for i, item in enumerate(L):
subitems = i
Ok Thanks a lot. And sadly not a typo, my bad logic overwriting values!
> To: tutor@python.org
> From: __pete...@web.de
> Date: Tue, 31 Mar 2015 17:50:01 +0200
> Subject: Re: [Tutor] Dynamic naming of lists
>
> Ian D wrote:
>
>> Thanks I will look into thes
Ian D wrote:
> Thanks I will look into these. The data going in is a list like
> this:['broadcast', '"d8on"', 'broadcast', '"d11on"']
>
> With the output beng something like this.
>
> lst_0 = ['broadcast', '"d8on"']
>
> lst_0 = ['broadcast', '"d11on"']
Is that a typo, did you mean
lst_1 = ['b
Thanks I will look into these. The data going in is a list like
this:['broadcast', '"d8on"', 'broadcast', '"d11on"']
With the output beng something like this.
lst_0 = ['broadcast', '"d8on"']
lst_0 = ['broadcast', '"d11on"']
I have managed to use a dictionary as advised in a post on StackOverfl
On 03/31/2015 10:00 AM, Ian D wrote:
Hi
I have a list that I am splitting into pairs of values. But the list is dynamic
in size. It could have 4 values or 6 or more.
I originally split the list into pairs, by using a new list and keep a pair in
the old list by just popping 2 values. But if th
Hi
I have a list that I am splitting into pairs of values. But the list is dynamic
in size. It could have 4 values or 6 or more.
I originally split the list into pairs, by using a new list and keep a pair in
the old list by just popping 2 values. But if the list is longer than 4 values.
I cann
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