On February 5, 2015 6:57:06 PM EST, Edgar Figueroa
wrote:
>Hello group. I'm trying to call the variable "name" within my input ()
You're not needing to call it, but to use it. The simplest answer is just to
print the prompt separately, and just call input ().
Next option is to build a st
On 05/02/15 23:57, Edgar Figueroa wrote:
name = input("Hello. What's your name? ")
print("\nHello", name, ". Nice to meet you.")
favFood1 = input("\n", name, ", what's your favorite food? ")
Obviously it isn't working.
You need to construct a single string argument.
There are several option
On Thu, Feb 5, 2015 at 3:57 PM, Edgar Figueroa wrote:
> Hello group. I'm trying to call the variable "name" within my input ()
> function.
> Here's what I have:
> name = input("Hello. What's your name? ")
> print("\nHello", name, ". Nice to meet you.")
> favFood1 = input("\n", name, ", what's yo
Hello group. I'm trying to call the variable "name" within my input ()
function.
Here's what I have:
name = input("Hello. What's your name? ")
print("\nHello", name, ". Nice to meet you.")
favFood1 = input("\n", name, ", what's your favorite food? ")
Obviously it isn't working. It tells me I hav
On Thu, Feb 05, 2015 at 11:30:38AM -0600, boB Stepp wrote:
> Python 2.4.4, Solaris 10.
>
> a_list = [item1, item2, item3]
> for item in a_list:
> print 'Item number', ???, 'is:', item
>
> Is there an easy, clever, Pythonic way (other than setting up a
> counter) to replace ??? with the curren
On 05/02/15 18:37, Timo wrote:
Op 05-02-15 om 18:48 schreef Alan Gauld:
try:
>>> help( enumerate() )
Should be
>>> help(enumerate)
True, good catch!
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog
On Thu, Feb 5, 2015 at 12:25 PM, Mark Lawrence wrote:
>
> We're now at 3.4 with 3.5 close to its first alpha release, so any
> particular reason that even 2.6 doesn't seem relevant to you? No axe to
> grind, just plain old fashioned curiosity :)
>
We are not allowed to install or upgrade software
On February 5, 2015 12:33:56 PM EST, Bob Williams
wrote:
>-BEGIN PGP SIGNED MESSAGE-
>Hash: SHA1
>
>On 05/02/15 14:59, DaveA wrote:
>>
>>
Sorry my last message was in html, and indentation trashed . I just installed
k9 on my tablet and hadn't yet found the setting for text-only. Le
Op 05-02-15 om 18:48 schreef Alan Gauld:
try:
>>> help( enumerate() )
Should be
>>> help(enumerate)
Timo
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
On 05/02/2015 18:03, boB Stepp wrote:
On Thu, Feb 5, 2015 at 11:48 AM, Alan Gauld wrote:
On 05/02/15 17:30, boB Stepp wrote:
Python 2.4.4, Solaris 10.
a_list = [item1, item2, item3]
for item in a_list:
print 'Item number', ???, 'is:', item
Is there an easy, clever, Pythonic way (other
On Thu, Feb 5, 2015 at 11:48 AM, Alan Gauld wrote:
> On 05/02/15 17:30, boB Stepp wrote:
>>
>> Python 2.4.4, Solaris 10.
>>
>> a_list = [item1, item2, item3]
>> for item in a_list:
>> print 'Item number', ???, 'is:', item
>>
>> Is there an easy, clever, Pythonic way (other than setting up a
>
On Thu, Feb 5, 2015 at 11:45 AM, Zachary Ware
wrote:
> On Thu, Feb 5, 2015 at 11:30 AM, boB Stepp wrote:
>> Python 2.4.4, Solaris 10.
>>
>> a_list = [item1, item2, item3]
>> for item in a_list:
>> print 'Item number', ???, 'is:', item
>>
>> Is there an easy, clever, Pythonic way (other than s
On 05/02/15 17:30, boB Stepp wrote:
Python 2.4.4, Solaris 10.
a_list = [item1, item2, item3]
for item in a_list:
print 'Item number', ???, 'is:', item
Is there an easy, clever, Pythonic way (other than setting up a
counter) to replace ??? with the current index of item in a_list?
try:
On Thu, Feb 5, 2015 at 11:30 AM, boB Stepp wrote:
> Python 2.4.4, Solaris 10.
>
> a_list = [item1, item2, item3]
> for item in a_list:
> print 'Item number', ???, 'is:', item
>
> Is there an easy, clever, Pythonic way (other than setting up a
> counter) to replace ??? with the current index of
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 05/02/15 14:59, DaveA wrote:
>
>
> On February 5, 2015 8:27:29 AM EST, Bob Williams
> wrote:
>> Hi,
>>
>> My script is running under Python 3.4.1 on a 64bit openSUSE
>> linux system. It is a backup script making calls to rsync and
>> btrfs-tools
Python 2.4.4, Solaris 10.
a_list = [item1, item2, item3]
for item in a_list:
print 'Item number', ???, 'is:', item
Is there an easy, clever, Pythonic way (other than setting up a
counter) to replace ??? with the current index of item in a_list?
--
boB
___
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 05/02/15 13:57, Mark Lawrence wrote:
> On 05/02/2015 13:27, Bob Williams wrote:
>
>>
>> I would like to reduce all those repeated calls to do_sync() in
>> main(), for example, to one by putting the *_srcpath and
>> *_*syncpath variables into list
On February 5, 2015 8:27:29 AM EST, Bob Williams
wrote:
>Hi,
>
>My script is running under Python 3.4.1 on a 64bit openSUSE linux
>system. It is a backup script making calls to rsync and btrfs-tools,
>and backing up several different paths. Here is the script, my question
>follows below:
>
>**C
On 05/02/2015 13:27, Bob Williams wrote:
I would like to reduce all those repeated calls to do_sync() in main(), for
example, to one by putting the *_srcpath and *_*syncpath variables into lists
(eg. source_list and sync_list) and using a for loop to get the first item out
of each list, then
Hi,
My script is running under Python 3.4.1 on a 64bit openSUSE linux system. It is
a backup script making calls to rsync and btrfs-tools, and backing up several
different paths. Here is the script, my question follows below:
**Code**
import datetime
import glob
import os, os.path
import subpro
20 matches
Mail list logo
