On 04/17/2013 08:12 PM, Alan Gauld wrote:
On 17/04/13 20:27, Danilo Chilene wrote:
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
pr
Hi! I was having a bit of nostalgia today, and thought I'd try to write a
simple, old school BBS. I found the 'paramiko' library, and I've got
something I can SSH into that would have impressed my 1990's self.
I found some example code of the "threading" library, and I've managed to
use it to ta
On 17/04/13 20:27, Danilo Chilene wrote:
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
print c
I run python file.py a and returns t
-- Forwarded message --
From: Danilo Chilene
Date: Wed, Apr 17, 2013 at 2:17 PM
Subject: Re: [Tutor] Sys.argv read parameters
To: Danny Yoo
Hello Danny,
The part that is changing is just the sys.argv[1]
The vars will have always the same content.
What I don't want is to hav
On 17/04/2013 20:27, Danilo Chilene wrote:
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
Forwarding message to Python-tutor mailing list. I did not realize
that your reply didn't show up for the rest of Python tutor. Please
use Reply to All in the future.
-- Forwarded message --
From: Danilo Chilene
Date: Wed, Apr 17, 2013 at 2:17 PM
Subject: Re: [Tutor] Sys.argv
On 04/17/2013 05:15 PM, Danny Yoo wrote:
Yup! Sorry about my tone for its stridency. But I just got concerned
that the original poster seemed content about turning the chain of if
statements into a table definition. To my mind, they're very closely
related, data and control. I'm trying to pus
Registration is open for three upcoming PyCamps produced by the Triangle
Python Users Group:
- A five-day PyOhio PyCamp hosted by the Ohio State University Open
Source Club, July 22-26, 2013 the week prior to the PyOhio regional
Python conference weekend. PyCamp is a training program and spons
Yup! Sorry about my tone for its stridency. But I just got concerned
that the original poster seemed content about turning the chain of if
statements into a table definition. To my mind, they're very closely
related, data and control. I'm trying to push the OP to realizing
that if they are doin
On 04/17/2013 04:49 PM, Danny Yoo wrote:
Wait. If the solution that we're stopping at to use a hashtable here,
that's not quite right.
Nothing wrong with a dict, if a proper specification of the problem were
available. Notice that in my solution, the messages were not all
trivially related
Wait. If the solution that we're stopping at to use a hashtable here,
that's not quite right. A good solution to this should be _much_
shorter, on the order of a one-liner. Hashtables are great, but
they're not the answer to everything.
If we're doing something like:
a -> "This is A"
b
Hello Dave,
1) I'm using Python 2.7
2) The program wasn't suppose to really work, was just a example.
3) You assumed correct.
That's was what I looking for, worked like charm.
Thanks!
On Wed, Apr 17, 2013 at 5:18 PM, Dave Angel wrote:
> On 04/17/2013 03:27 PM, Danilo Chilene wrote:
>
>> Dear
On Wed, Apr 17, 2013 at 1:03 PM, Danny Yoo wrote:
> ##
> ## double: string -> string
> def double(x):
> return x + x
>
>
> ## For example, a blast from the past:
> print "The Noid says: " + double("pizza")
> ##
>
I'm sorry, but this is a bug.
On 04/17/2013 03:27 PM, Danilo Chilene wrote:
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c
What's the part that's "changing"? What's the part that stays the same?
I would recommend thinking of this in terms of a function.
Can you write a function that consumes a letter l and returns the
string "This is ..." where "..." is the uppercased l?
As an example of a simple function on string
Dear Python Tutor,
I have the code below(file.py):
import sys
a = 'This is A'
b = 'This is B'
c = 'This is C'
for i in sys.argv[1]:
if sys.argv[1] == 'a':
print a
if sys.argv[1] == 'b':
print b
if sys.argv[1] == 'c':
print c
I run python file.py a and return
Op 17-04-13 18:09, Jim Mooney schreef:
The script 2to3.py is run from the system's terminal/console shell
(e.g. cmd or PowerShell on Windows), not the python shell.
Yay, it worked! A decade of Windows and I'm back to the DOS Command
Line ;')
If you want to program, the command line is your frien
> The script 2to3.py is run from the system's terminal/console shell
> (e.g. cmd or PowerShell on Windows), not the python shell.
Yay, it worked! A decade of Windows and I'm back to the DOS Command
Line ;') Well, it worked the second time.I thought I could do without
the -w but nothing happened.
Hi,
On 17 April 2013 06:11, Jim Mooney wrote:
> > Generally the 2to3 script does an OK job. If you're using Windows it's
> > [Python_Dir]\Tools\Scripts\2to3.py.
> >
> > http://docs.python.org/3/library/2to3
>
>
> Thanks. I didn't know where to find it and though
On Wed, Apr 17, 2013 at 1:11 AM, Jim Mooney wrote:
2to3 loops.py
> File "", line 1
> 2to3 loops.py
>^
> SyntaxError: invalid syntax
The script 2to3.py is run from the system's terminal/console shell
(e.g. cmd or PowerShell on Windows), not the python shell.
If the current dire
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