You forgot to include the list. So I'm forwarding it now, with new remarks.
On 07/20/2012 01:47 AM, wolfrage8...@gmail.com wrote:
> On Fri, Jul 20, 2012 at 12:33 AM, Dave Angel wrote:
>
>> On 07/19/2012 05:55 PM, Prasad, Ramit wrote:
I am not sure how to answer that question because all fi
On Fri, Jul 20, 2012 at 12:33 AM, Dave Angel wrote:
> On 07/19/2012 05:55 PM, Prasad, Ramit wrote:
> >> I am not sure how to answer that question because all files are binary,
> >> but the files that I will parse have an encoding that allows them to be
> >> read in a non-binary output. But my p
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On 20/07/12 10:45, Dave Angel wrote:
On 07/19/2012 08:36 PM, Osemeka Osuagwu wrote:
...
99 ninety nine
100 onehundred
101 one hundred and one
102 one hundred and two
103 one hundred and three
104 one hundred and four
105 one hundred and five
106 one hundred and six
107 one hundred and seven
108
On 07/19/2012 08:36 PM, Osemeka Osuagwu wrote:
> ...
> 99 ninety nine
> 100 onehundred
> 101 one hundred and one
> 102 one hundred and two
> 103 one hundred and three
> 104 one hundred and four
> 105 one hundred and five
> 106 one hundred and six
> 107 one hundred and seven
> 108
>
> Traceback (mos
On Thu, Jul 19, 2012 at 5:32 PM, Jordan wrote:
>
> I am not sure how to answer that question because all files are binary,
> but the files that I will parse have an encoding that allows them to be
> read in a non-binary output. But my program will not use the in a
> non-binary way, that is why I p
Hi folks,
I've been trying to convert numbers from digits to words, I wrote the
following code;
units = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight',
'nine']
teens = ['eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen',
'seventeen', 'eighteen', 'nineteen']
tens = [
On Thu, Jul 19, 2012 at 4:21 PM, Dave Angel wrote:
> On 07/19/2012 06:58 PM, Alexander Q. wrote:
> > I have this little program that is supposed to calculate how many
> diagonals
> > a polygon of x sides has, but it does not return what I have in the
> > "return" part of the function when I call
On 20/07/12 00:17, Prasad, Ramit wrote:
def num_diag(var):
ans = 0
if var <= 3:
print("No diagonals.")
else:
for i in range(num_sides - 3):
ans = ans + i
return (((var - 3)*2) + ans)
num_sides = (int(raw_input("Enter sides: ")))
num_diag(num_sides)
NameError:
Hi All,
I have a few lists that I'm trying to put into a dictionary based on
which list the user wants to use as a filter. If the user selects 1
the the dictionary would be created using the first list as the keys
and the secondary items as the values. If the user selects 2, the
dictionary would b
On 07/19/2012 06:58 PM, Alexander Q. wrote:
> I have this little program that is supposed to calculate how many diagonals
> a polygon of x sides has, but it does not return what I have in the
> "return" part of the function when I call it. Here is the code:
>
> def num_diag(var):
> ans = 0
> if
On 7/19/2012 3:58 PM Alexander Q. said...
I have this little program that is supposed to calculate how many
diagonals a polygon of x sides has, but it does not return what I have
in the "return" part of the function when I call it. Here is the code:
def num_diag(var):
ans = 0
if var <= 3:
> I have this little program that is supposed to calculate how many diagonals a
> polygon of x sides has, but it does not return what I have in the "return"
> part of the function when I call it. Here is the code:
>
> def num_diag(var):
> ans = 0
> if var <= 3:
> print("No diagonals.")
>
On 7/19/2012 4:10 PM Emile van Sebille said...
I found ~200k files in /var/log all but 227 look like:
Sorry -- my bad.
Emile
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I found ~200k files in /var/log all but 227 look like:
list_boxes.day.1.gz.1.gz.1.gz.3.gz.1.gz.1.gz.2.gz.1.gz.1.gz.2.gz.1.gz
list_boxes.day.1.gz.1.gz.1.gz.3.gz.1.gz.1.gz.2.gz.1.gz.1.gz.2.gz.1.gz.1.gz
list_boxes.day.1.gz.1.gz.1.gz.3.gz.1.gz.1.gz.2.gz.1.gz.1.gz.2.gz.1.gz.1.gz.1.gz
list_boxes.day.1.
I have this little program that is supposed to calculate how many diagonals
a polygon of x sides has, but it does not return what I have in the
"return" part of the function when I call it. Here is the code:
def num_diag(var):
ans = 0
if var <= 3:
print("No diagonals.")
else:
for i i
On 07/19/2012 05:55 PM, Prasad, Ramit wrote:
>> I am not sure how to answer that question because all files are binary,
>> but the files that I will parse have an encoding that allows them to be
>> read in a non-binary output. But my program will not use the in a
>> non-binary way, that is why I pl
Selby Rowley-Cannon wrote:
I am using a hash table in a small randomization program. I know that
some hash functions can be prone to collisions, so I need a way to
detect collisions.
I doubt that very much.
This entire question seems like a remarkable case of premature optimization.
Start wi
> I am not sure how to answer that question because all files are binary,
> but the files that I will parse have an encoding that allows them to be
> read in a non-binary output. But my program will not use the in a
> non-binary way, that is why I plan to open them with the 'b' mode to
> open them
On 07/19/2012 10:48 PM, Prasad, Ramit wrote:
OK. I am using one time pads to XOR data, but the one time pads (keys)
are very large numbers, converting them to binary increases their size
exponentially, which allows me to get more XORing done out of a single
>>> You want
> > bin_data = [ bin(ord(char)).split('b')[1].zfill(8) for char in data ]
> > bin_string = ''.join(bin_data)
> > bin_list = [ chr( int(char, 2) ) for char in bin_data ]
> Thank you exactly what I was looking for!
> >
> > I am not really sure what you are getting at with XOR and one time
> > padding
On 07/18/2012 05:07 PM, Jordan wrote:
> OK so I have been trying for a couple days now and I am throwing in the
> towel, Python 3 wins this one.
I should have paid more attention to this the first time. Clearly you
don't want help.
--
DaveA
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Tut
> >>
> >>
> >> OK. I am using one time pads to XOR data, but the one time pads (keys)
> >> are very large numbers, converting them to binary increases their size
> >> exponentially, which allows me to get more XORing done out of a single
> > You want to explain this impossibility of increasing siz
Sorry, I am not sure why Thunderbird is stripping the spaces, may have
something to do with a plug-in that I have installed, I will have to
look into it.
On 07/19/2012 10:41 PM, Prasad, Ramit wrote:
> Sure, this makes perfect sense to me :) (adding indent)
>
> for char in data:
> bin_data += b
On 07/19/2012 10:04 PM, eryksun wrote:
> On Thu, Jul 19, 2012 at 3:08 PM, Jordan wrote:
> I'm not an expert with cryptography, but here's a simple XOR example:
from itertools import cycle
text = b'Mary had a little lamb.'
key = b'1234'
cypher = bytes(x^y for x,y in zip(text,
> > bin(integer).split('b')[1].zfill( multiple_of_eight )
> OK so using this: Hopefully my copy paste works this time.
>
> bin_data = ''
>
> for char in data:
>
> bin_data += bin(ord(char)).split('b')[1].zfill(8)
>
> print(bin_data)
>
> bin_list = [bin_data[x:x + 2] for x in range(0, len(bin_d
On 07/19/2012 09:53 PM, Dave Angel wrote:
> On 07/19/2012 03:19 PM, Jordan wrote:
>>
>>
>> OK. I am using one time pads to XOR data, but the one time pads (keys)
>> are very large numbers, converting them to binary increases their size
>> exponentially, which allows me to get more XORing done ou
On Thu, Jul 19, 2012 at 3:08 PM, Jordan wrote:
>
> size = 8 * max(len(b3), len(b4))
> format(r, "0%db" % size)
>> '0011001100110011'
> Is this output the output for size rather than the two variables joined
> together?
Using "format" is useful if you need the string to be
On 07/19/2012 09:23 PM, Prasad, Ramit wrote:
>> A question I have for the group before I respond is a option that I saw
>> that I had earlier was to ord() each element of a string and then bin()
>> that number. But since bin() produces a string I could not figure out
>> the correct way to attach
On 07/19/2012 03:19 PM, Jordan wrote:
>
>
> OK. I am using one time pads to XOR data, but the one time pads (keys)
> are very large numbers, converting them to binary increases their size
> exponentially, which allows me to get more XORing done out of a single
You want to explain this impossibili
On 7/19/2012 12:29 PM Selby Rowley-Cannon said...
I am using a hash table in a small randomization program. I know that
some hash functions can be prone to collisions, so I need a way to
detect collisions.
The 'hash value' will be stored as a variable. I do not want to check it
against each singu
I am using a hash table in a small randomization program. I know that
some hash functions can be prone to collisions, so I need a way to
detect collisions.
The 'hash value' will be stored as a variable. I do not want to check it
against each singular hash value, as there will be many; I need a w
> A question I have for the group before I respond is a option that I saw
> that I had earlier was to ord() each element of a string and then bin()
> that number. But since bin() produces a string I could not figure out
> the correct way to attach two bin() outputs back together again due to
> the
On 07/19/2012 08:53 PM, Prasad, Ramit wrote:
>>> I think your basic problem is too much conversion because you do not
>>> understand the types. A string is represented by a series of bytes
>>> which are binary numbers. Do you understand the concept behind ASCII?
>>> Each letter has a numeric repr
A question I have for the group before I respond is a option that I saw
that I had earlier was to ord() each element of a string and then bin()
that number. But since bin() produces a string I could not figure out
the correct way to attach two bin() outputs back together again due to
the leading 'b
My response is down lower, thank you Wayne.
On 07/19/2012 12:52 PM, Wayne Werner wrote:
> I'll preface my response by saying that I know/understand fairly
> little about
> it, but since I've recently been smacked by this same issue when
> converting
> stuff to Python3, I'll see if I can explain it
> > I think your basic problem is too much conversion because you do not
> > understand the types. A string is represented by a series of bytes
> > which are binary numbers. Do you understand the concept behind ASCII?
> > Each letter has a numeric representation that are sequential. So the
> > stri
On 07/19/2012 12:46 PM, Dave Angel wrote:
> On 07/19/2012 01:41 AM, wolfrage8...@gmail.com wrote:
>> On Thu, Jul 19, 2012 at 12:16 AM, Dave Angel wrote:
> That was just the first line that was not indented. If I thought you
> had a one-line while loop, I certainly would have just indented it.
> > Just to show you your original message contained no indentation
> > whatsoever. You might want to check your mail client settings and do
> > some experiments to make sure that indentation spaces are let through
> > unmolested and not stripped anywhere, otherwise the current little
> > brouhaha
On 07/19/2012 10:29 AM, Walter Prins wrote:
> Hi,
>
> Just to show you your original message contained no indentation
> whatsoever. You might want to check your mail client settings and do
> some experiments to make sure that indentation spaces are let through
> unmolested and not stripped anywh
On 07/19/2012 08:14 AM, Mark Lawrence wrote:
> On 19/07/2012 06:41, wolfrage8...@gmail.com wrote:
>> On Thu, Jul 19, 2012 at 12:16 AM, Dave Angel wrote:
>>
>
> Really? Are you using a forked version of Python that doesn't need
> indentation after a while loop, or are you speaking with a forked
On 07/19/2012 12:15 AM, Prasad, Ramit wrote:
> I think your basic problem is too much conversion because you do not
> understand the types. A string is represented by a series of bytes
> which are binary numbers. Do you understand the concept behind ASCII?
> Each letter has a numeric representat
> I would get a new list as:
>
> [(0, '3eA', 'Dupont', 'Juliette', '11.0/10.0', '4.0/5.0', '17.5/30.0',
> '3.0/5.0', '4.5/10.0', '35.5/60.0'), (1, '3eA', 'Pop', 'Iggy',
> '12.0/10.0', '3.5/5.0', '11.5/30.0', '4.0/5.0', '5.5/10.0',
> '7.5/10.0', '40.5/60.0')]
>
> ... from this one:
>
> [(0, '3eA'
You may use 'set'.
e.g.
===
>>> x
[(1, 2, 3), (1, 1), (2, 2), (1, 1), (2, 2)]
>>> set(x)
set([(2, 2), (1, 1), (1, 2, 3)])
===
On 19-Jul-2012, at 11:03 PM, PyProg PyProg wrote:
> Hi all,
>
> I would get a new list as:
>
> [(0, '3eA', 'Dupont', 'Juliette', '11.0/10.0', '4.0/5.0', '17.5/30.0',
>
On 19/07/12 09:09, Bala subramanian wrote:
Friends,
At present i write programs using vi editor. I am interested to change
to something else. My specific need is that i want to select a
portion/small segment of my program (for eg. a nested loop) and then
monitor processing time it takes for that
Oh I forgot to mention, with Python 2 (2.7).
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Hi all,
I would get a new list as:
[(0, '3eA', 'Dupont', 'Juliette', '11.0/10.0', '4.0/5.0', '17.5/30.0',
'3.0/5.0', '4.5/10.0', '35.5/60.0'), (1, '3eA', 'Pop', 'Iggy',
'12.0/10.0', '3.5/5.0', '11.5/30.0', '4.0/5.0', '5.5/10.0',
'7.5/10.0', '40.5/60.0')]
... from this one:
[(0, '3eA', 'Dupont',
https://www.youtube.com/watch?v=sgHbC6udIqc
This is a very good talk on Unicode which was done at PyCon US 2012.
It helped me a lot to understand the pain.
Greets
Sander
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On Thu, 19 Jul 2012, Bala subramanian wrote:
Friends,
At present i write programs using vi editor. I am interested to change to
something else. My specific need is that i want to select a portion/small
segment of my
program (for eg. a nested loop) and then monitor processing time it takes for
On Thu, Jul 19, 2012 at 1:41 AM, wolfrage8...@gmail.com
wrote:
>
> I was comparing them but I think I understand how to compare them well, now
> I want to convert them both to binary so that I can XOR them together. Thank
> you for your time and help Dave, now I need to reply to Ramit.
A bytes ob
Just a few notes...
On Wed, 18 Jul 2012, Ryan Waples wrote:
import glob
my_in_files = glob.glob ('E:/PINK/Paired_End/raw/gzip/*.fastq')
for each in my_in_files:
#print(each)
out = each.replace('/gzip', '/rem_clusters2' )
#print (out)
INFILE = open (each, 'r')
I'll preface my response by saying that I know/understand fairly little about
it, but since I've recently been smacked by this same issue when converting
stuff to Python3, I'll see if I can explain it in a way that makes sense.
On Wed, 18 Jul 2012, Jordan wrote:
OK so I have been trying for a c
On 07/19/2012 01:41 AM, wolfrage8...@gmail.com wrote:
> On Thu, Jul 19, 2012 at 12:16 AM, Dave Angel wrote:
>
>>
>> I don't get the same error you did. I get:
>>
>> File "jordan.py", line 13
>> test_int = int(str(test_int) + str(int.from_bytes(os.urandom(1),
>> 'big')))
>>^
>>
>
Try Sublime,
On Thu, Jul 19, 2012 at 1:39 PM, Bala subramanian wrote:
> Friends,
> At present i write programs using vi editor. I am interested to change to
> something else. My specific need is that i want to select a portion/small
> segment of my program (for eg. a nested loop) and then monito
Friends,
At present i write programs using vi editor. I am interested to change to
something else. My specific need is that i want to select a portion/small
segment of my program (for eg. a nested loop) and then monitor processing
time it takes for that portion while i run the program. By this i ho
On 19/07/12 07:00, Steven D'Aprano wrote:
def four_lines(file_object):
line1 = next(file_object).strip()
# Get the next three lines, padding if needed.
line2 = next(file_object, '').strip()
line3 = next(file_object, '').strip()
> I count only 19 lines.
yep, you are right. My bad, I think I missing copy/pasting line 20.
>The first group has only three lines. See below.
Not so, the first group is actually the first four lines listed below.
Lines 1-4 serve as one group. For what it is worth, line four should
have 1 cha
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