On 13/12/11 20:39, Kaixi Luo wrote:
I want to create a list of lists of lists (listB) from a list of lists
(listA). Below there's a snippet of my code:
listA = [[] for i in range(9)]
listB = [[] for i in range(3)]
So list A containds 9 empty lists
And list B contains 3 empty lists
count = 0
On 12/13/2011 3:26 PM Kaixi Luo said...
Uh, sorry. I made some very bad typos there. It should be:
listA = [[] for i in range(9)]
# some code here...
listB = [[] for i in range(3)]
count = 0
for i in range(3):
for j in range(3):
listB[i].append(listA[count])
count+=1
Forgot to reply all...
-- Forwarded message --
From: Rich Lovely
Date: 13 December 2011 23:17
Subject: Re: [Tutor] A shorter way to initialize a list?
To: Kaixi Luo
On 13 December 2011 20:39, Kaixi Luo wrote:
> Hello,
>
> I want to create a list of lists of lists (listB) from
On Tue, Dec 13, 2011 at 10:09 PM, Emile van Sebille wrote:
> On 12/13/2011 12:39 PM Kaixi Luo said...
>
> Hello,
>>
>> I want to create a list of lists of lists (listB) from a list of lists
>> (listA). Below there's a snippet of my code:
>>
>> list1 = [[] for i in range(9)]
>>
>
> Should this be
Kaixi Luo wrote:
Hello,
I want to create a list of lists of lists (listB) from a list of lists
(listA). Below there's a snippet of my code:
list1 = [[] for i in range(9)]
# some code here...
listA = [[] for i in range(3)]
count = 0
for i in range(3):
for j in range(3):
listB[i].ap
From: tutor-bounces+ramit.prasad=jpmorgan@python.org
[mailto:tutor-bounces+ramit.prasad=jpmorgan@python.org] On Behalf Of Kaixi
Luo
Sent: Tuesday, December 13, 2011 2:39 PM
To: tutor@python.org
Subject: [Tutor] A shorter way to initialize a list?
Hello,
I want to create a list of lists
On 12/13/2011 12:39 PM Kaixi Luo said...
Hello,
I want to create a list of lists of lists (listB) from a list of lists
(listA). Below there's a snippet of my code:
list1 = [[] for i in range(9)]
Should this be listB?
# some code here...
listA = [[] for i in range(3)]
count = 0
for i in ra
Hello,
I want to create a list of lists of lists (listB) from a list of lists
(listA). Below there's a snippet of my code:
list1 = [[] for i in range(9)]
# some code here...
listA = [[] for i in range(3)]
count = 0
for i in range(3):
for j in range(3):
listB[i].append(listA[count])
Op 12-12-11 20:46, rail shafigulin schreef:
i found something interesting during the timedate difference calculation
import datetime
import time
def main():
mydatetime = datetime.datetime.now()
time.sleep(1)
mydatetime2 = datetime.datetime.now()
diff = mydatetime - mydatetime2
Lie Ryan