Hello,
I have a very simple question / problem I need answered. The problem
is imnot entirely sure of the correct terminology and langauge to use
to describe it. (One of the reasons im using this miling list)
I have a 2d matrix representing the X the Y and the Z value of a
point. I wish to con
"Carla Jenkins" wrote
When I try using trajectory I receive an error.
What is trajectory? Its not a standard Python function
so we can't be too helpful in fixing errors unless we
know more about it.
Here is the code:
def logistic(x):
return 4*x*(1-x)
This is OK so far...
ds_l
Thanks Steve, your are, from now on, my guru
this is the final version, the
good one!
contents = re.sub(r'(|)(l|L|n|N|t|T)(|)', r"\2'" ,contents)
On Wed, March 30, 2011 17:27, Steve Willoughby wrote:
On 30-Mar-11 08:21,
"Andrés Chandía" wrote:
>
>
> Thanks Kushal
and Steve.
> I think it w
On 30-Mar-11 08:21, "Andrés Chandía" wrote:
Thanks Kushal and Steve.
I think it works,a I say "I think" because at the
results I got a strange character instead of the letter that should appear
this is
my regexp:
contents = re.sub(r'(|)(l|L|n|N|t|T)(|)', '\2\'' ,contents)
Remember that \2 i
Thanks Kushal and Steve.
I think it works,a I say "I think" because at the
results I got a strange character instead of the letter that should appear
this is
my regexp:
contents = re.sub(r'(|)(l|L|n|N|t|T)(|)', '\2\'' ,contents)
this is my input file content:
lomo
nomo
tomo
Lomo
Nomo
On 3/30/2011 7:26 AM Carla Jenkins said...
I am new to Python learnig for a class. When I try using trajectory I receive
an error. Here is the code:
def logistic(x):
return 4*x*(1-x)
ds_logistic11=trajectory(logistic,0.11)
SyntaxError: invalid syntax
Hi Carla,
Be sure to copy and
I am new to Python learnig for a class. When I try using trajectory I receive
an error. Here is the code:
def logistic(x):
return 4*x*(1-x)
ds_logistic11=trajectory(logistic,0.11)
SyntaxError: invalid syntax
Sincerely,
Carla Jenkins
___
Tutor
2011/3/30 "Andrés Chandía" :
>
>
> I'm new to this list, so hello everybody!.
>
Hello Andrés
> The stuff:
>
> I'm working with
> regexps and this is my line:
>
> contents = re.sub("l<\/u>",
> "le" ,contents)
>
> in perl there is a way to reference previous registers,
> i.e.
>
> $text =~ s/(l|L|n|
On 29-Mar-11 23:55, Alan Gauld wrote:
""Andrés Chandía"" wrote
in perl there is a way to reference previous registers,
$text =~ s/(l|L|n|N)<\/u>/$1e/g;
I'm looking for the way to do it in python
If you're using just a straight call to re.sub(), it works like this:
text = re.sub(r
ranjan das wrote:
> I have the following list
>
> List=[( 'G1', 'CFS', 'FCL', 'R1' ),('G3', 'LOOSEFREIGHT', 'MIXEDLCL',
> 'R9'),
> ('G4', 'CFS', 'FCL', 'R10' ), ('G2', 'LOOSEFREIGHT', 'LCL', 'R4' ),
> ('G1',
> 'CFS', 'FCL', 'R2' ), ('G2', 'LOOSEFREIGHT', 'LCL', 'R5') ]
>
>
> now I want to gro
You are right, lambda lis: lis[1:3] would be more readable
2011/3/30 Sander Sweers
> On 30 March 2011 00:30, Alan Gauld wrote:
> > Wouldn't you just return a tuple of the two elements?
> >
> > Or am I missing something having jumped into the middle of the thread...
>
> Ah yes, you are correct.
""Andrés Chandía"" wrote
I'm new to this list, so hello everybody!.
Hi, welcome to the list.
Please do not use reply to start a new thread it confuses threaded
readers and may mean you message will not be seen. Also please
supply a meaningful subject (as above) so we can decide if it
looks
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