Thank you all for your replies. I wonder why I din't get any updates from the
mailing list. Now I feel I have more reasons to proceed with the implementation.
Only that I don't know where to start :)
Thanks,
Mahesh Narayanamurthi
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Tutor maillist -
" A more important problem is that it is flattening only one level.
Multi-level flattening is I think not possible without using some kind
of recursion."
Not true, just requires more iterations to check each element. Each iteration
could check if every element is a list and then unpack if it is a
On Fri, Mar 25, 2011 at 1:54 PM, Walter Prins wrote:
>
>
> On 25 March 2011 18:26, Rance Hall wrote:
>>
>> config_version = config.get('versions','configver',0)
>>
>> This line fails under 3.2 Linux with the error message:
>>
>> TypeError: get() takes exactly 3 positional arguments (4 given)
>>
Hey List,
In Perl, I can manipulate a special variable called $| to control
buffered output, even on web pages, so I can watch something run (like
CGI processes reading files or running system commands) as Perl
processes it (pseudo real-time), as opposed to languages like PHP which
buffers al
have you tried help(config.get) in the python interactive shell?
--
Joel Goldstick
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Ugh, please excuse my tardiness and ignore the numbered items below my
signature which I was intending to delete, I accidentally hit "end" before I
cleaned up the post... :red faced:
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On 25 March 2011 18:26, Rance Hall wrote:
> config_version = config.get('versions','configver',0)
>
> This line fails under 3.2 Linux with the error message:
>
> TypeError: get() takes exactly 3 positional arguments (4 given)
>
> What could the 4th argument be? I only see three.
>
> This same
I wrote a script on a windows box for python 3.1 after a meeting with
the client for this project we agreed to port it to Linux so that I
could make use of enscript and ps2pdf to email customers documents
right from the script.
Client uses a Centos server so I did some reading and installed pytho
On 25/03/2011 16:11, Robert Sjoblom wrote:
I received your email just as I left my computer, and didn't want to
type out an answer on my phone (because smartphones aren't smart
enough for that yet), and my first reaction was "why?" followed by "I
need my program to continue even if I get the err
On Fri, Mar 25, 2011 at 5:11 PM, Robert Sjoblom
wrote:
> -- Hugo Arts wrote --
>
>>Why are you asking for the user to enter a key? you're iterating over
>>all keys in the dictionary, so there's no need to ask the user for
>>keys, you already know them. Why not do this:
>
>>b = int(input("Enter val
-- Hugo Arts wrote --
>Why are you asking for the user to enter a key? you're iterating over
>all keys in the dictionary, so there's no need to ask the user for
>keys, you already know them. Why not do this:
>b = int(input("Enter value for key %s: " % key))
>dictionary[key] = b
I have a great an
I have recently become a tutor to several Python students.
I enjoy tutoring and they benefit from it.
I work with some students using remote access, so we can be
geographically far apart.
Who do you know who might benefit from receiving one-on-one tutoring?
--
Bob Gailer
919-636-4239
Cha
On Fri, Mar 25, 2011 at 7:52 AM, Robert Sjoblom wrote:
> Hi again, list! A quick question about dictionary behaviour. I have a
> dictionary of keys, and the user should be able to enter values into
> said dictionary. My idea was this:
>
> def addData(key, value):
>dictionary[key] += int(value)
In addition I think defaultdict doesn't avoid neither entering negatives nor
something that isn't an integer, you could try something like this:
>>> dictionary = {}
>>> for _ in range(4):
key = input("Enter key: ")
value = 0
while value <= 0:
try:
value = int(input(
On Fri, Mar 25, 2011 at 12:52 PM, Robert Sjoblom
wrote:
> Hi again, list! A quick question about dictionary behaviour. I have a
> dictionary of keys, and the user should be able to enter values into
> said dictionary. My idea was this:
>
> def addData(key, value):
> dictionary[key] += int(value
I am a newbie too, but
from collections import defaultdict
Then you can do:
data = defaultdict(int)
Everything (all keys) start at 0, so you can do "+=" with no problem.
I'm sure somebody else has a better solution though!
Cheers
Colin
On 25 March 2011 18:52, Robert Sjoblom wrote:
> Hi ag
Hi again, list! A quick question about dictionary behaviour. I have a
dictionary of keys, and the user should be able to enter values into
said dictionary. My idea was this:
def addData(key, value):
dictionary[key] += int(value)
return None
dictionary = {"a":0, "b":0, "c":0, "d":0}
for k
Lea Parker wrote:
Message 3 - I solved my problem. Yah Me!!!
Thanks
P.S I hope this is the right way to let you know so you don't waste your
time.
Hi Lea, glad you solved the problem, and welcome.
For the future though, when replying to a digest, you should edit the
subject line to be so
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