Here's a little 'anomaly' though, programmers say hammer when the
truth is, that modern construction should use pneumatic tools, as in
air hammer.
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Maybe I missed it, even in the google searches/manuals, but does
someone know of an introduction to python interpolation that show the
different forms of %
, as in %s = string, and %d = digit(i think, or correct me).
TIA,
David
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On Sat, Oct 9, 2010 at 2:12 AM, Steven D'Aprano wrote:
> On Sat, 9 Oct 2010 03:15:35 pm you wrote:
>
>> > You should use that. It works, it is tested and thoroughly
>> > debugged, and it is powerful.
>>
>> Certainly so, but not as powerful as the individual's ingenuity in
>> solving the problem at
On Sat, 9 Oct 2010 03:15:35 pm you wrote:
> > You should use that. It works, it is tested and thoroughly
> > debugged, and it is powerful.
>
> Certainly so, but not as powerful as the individual's ingenuity in
> solving the problem at hand without foreknowledge of the 'known'
> solution.
I suppos
On Fri, Oct 8, 2010 at 11:55 PM, Steven D'Aprano wrote:
> On Sat, 9 Oct 2010 06:34:44 am Susana Iraiis Delgado Rodriguez wrote:
>> Hello members:
>> I developed a Python module to make a list which contains all the
>> files ending with .shp and .dbf extensions, I have solved this
>> already,
>
>
>
On Sat, 9 Oct 2010 06:34:44 am Susana Iraiis Delgado Rodriguez wrote:
> Hello members:
> I developed a Python module to make a list which contains all the
> files ending with .shp and .dbf extensions, I have solved this
> already,
I'm sorry to tell you that you've just reinvented the wheel. This
Hi !
Being Python as rich in libraries, probably there's already a library
to create .XLS files.
Before finding that, you can try the CSV format: simply put a comma to
separate any fields you want in your values.
And of course, a comma will finish your line.
That way, Excel or any other spreads
On 10/8/2010 12:34 PM Susana Iraiis Delgado Rodriguez said...
Hello members:
I developed a Python module to make a list which contains all the files
ending with .shp and .dbf extensions, I have solved this already, but now I
want to write an excel file from it. The file should show the full path
On Fri, Oct 8, 2010 at 7:58 AM, Sithembewena Lloyd Dube
wrote:
> I realise that one cannot have a half integer :) I meant how would one
> round off to the first decimal nearest to either 0.5, or a whole number.
>
> Ugh...does anyone get what I'm trying to articulate? :)
sample input/output cases
On 8 October 2010 20:34, Susana Iraiis Delgado Rodriguez <
susana.delgad...@utzmg.edu.mx> wrote:
> Hello members:
> I developed a Python module to make a list which contains all the files
> ending with .shp and .dbf extensions, I have solved this already, but now I
> want to write an excel file fr
Hello members:
I developed a Python module to make a list which contains all the files
ending with .shp and .dbf extensions, I have solved this already, but now I
want to write an excel file from it. The file should show the full path from
the found files. This is the code:
import os
a = open ("di
On Fri, 8 Oct 2010 02:23:27 am Juan Jose Del Toro wrote:
> Dear List;
>
> In your experience what is the best IDE for Python?
None of them.
I use a good editor in one window (I prefer Kate for larger projects,
although Kwrite is good enough for single modules or scripts) and a
good xterm in an
On 08/10/2010 16.54, Roelof Wobben wrote:
...
Hello Franceso,
Thank you for the answer.
You're welcome.
Now find ot how i can find the dict which contains a team.
I thinking now of something like this.
teller = 1
For wedstrijd in tournooi :
if wedstrijd['thuis'] != stand ['ploeg'] :
On Fri, Oct 8, 2010 at 10:27 AM, Susana Iraiis Delgado Rodriguez <
susana.delgad...@utzmg.edu.mx> wrote:
> Hi Alan:
>
> The ouput is coming from a cicle and some functions that I vae to do to
> execute an ogr2ogr command, in this output I ask the user for the name of a
> file and then make a modul
Evert,
You're guess was right, copying the code from the email message worked. My IDE
- Eclipse/PyDev - must have been hiding the control character. I had tried
copying my code out to a text editor and back before asking for help, but it
didn't work. Perhaps I didn't "select all" before pasting
> From: rwob...@hotmail.com
> To: f...@libero.it
> Subject: RE: [Tutor] list of dict question
> Date: Fri, 8 Oct 2010 14:53:53 +
>
>
>
>
>
> Date: Fri, 8 Oct 2010 13:40:04 +0200
> From: f...@libero.it
> To: tut
> @Evert, I didn't figure out that your response was a solution, thought it was
> a question. Must be coffee time :P
>
> I tried it and, for instance, the rounded value (9) / 2 gave me 4.0 Couldn't
> get it until I noticed that @Joel divided the roudned figure by a decimal
> 2.0. That gave 4.5,
Besides, If I print the query, I have the next output:
C:/Archivos de programa/FWTools2.4.7/bin/ogr2ogr U3B-BARDA
.shp -where "LAYER='U3B-BARDA
'" tapalpa_05_plani_line.shp
C:/Archivos de programa/FWTools2.4.7/bin/ogr2ogr N2H-TEMP
.shp -where "LAYER='N2H-TEMP
'" tapalpa_05_plani_line.shp
C:/
Hi Alan:
The ouput is coming from a cicle and some functions that I vae to do to
execute an ogr2ogr command, in this output I ask the user for the name of a
file and then make a module to get to the subprocess part:
import shlex, subprocess, sys
from dbf import *
def process():
#Read dbfile statu
@Evert, I didn't figure out that your response was a solution, thought it
was a question. Must be coffee time :P
I tried it and, for instance, the rounded value (9) / 2 gave me 4.0 Couldn't
get it until I noticed that @Joel divided the roudned figure by a decimal
2.0. That gave 4.5, which is what
Thanks everyone,
I need to round to the nearest half (finally occured).
Made some chnages to Wayne's code as follows:
x = 4.4348
if x % 1 >= 0.5:
round(x) # gives 5.0 if the the value of the expression x % 1 exceeds
0.5
else:
x = round(x) + 0.5 # gives 4.5, as in this case.
Many thanks!
On Fri, Oct 8, 2010 at 9:00 AM, Evert Rol wrote:
> > I realise that one cannot have a half integer :) I meant how would one
> round off to the first decimal nearest to either 0.5, or a whole number.
> >
> > Ugh...does anyone get what I'm trying to articulate? :)
>
> Multiply by 2, round(), divide
> I realise that one cannot have a half integer :) I meant how would one round
> off to the first decimal nearest to either 0.5, or a whole number.
>
> Ugh...does anyone get what I'm trying to articulate? :)
Multiply by 2, round(), divide by 2?
>
> On Fri, Oct 8, 2010 at 2:51 PM, Sithembewena
On Fri, Oct 8, 2010 at 7:51 AM, Sithembewena Lloyd Dube
wrote:
> Hi folks,
>
> Supposing I had the float 4.4348 and I wished to round it off to the
> nearest half-integer upwards or downwards, how would I go about it?
>
You can use round:
round(4.4348) -> 4.0
But if you want to specify the beha
I realise that one cannot have a half integer :) I meant how would one round
off to the first decimal nearest to either 0.5, or a whole number.
Ugh...does anyone get what I'm trying to articulate? :)
On Fri, Oct 8, 2010 at 2:51 PM, Sithembewena Lloyd Dube
wrote:
> Hi folks,
>
> Supposing I had t
Hi folks,
Supposing I had the float 4.4348 and I wished to round it off to the nearest
half-integer upwards or downwards, how would I go about it?
Many thanks...
--
Regards,
Sithembewena Lloyd Dube
http://www.lloyddube.com
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Tutor maillist - Tutor
Il 08/10/2010 10.02, Alan Gauld ha scritto:
"Roelof Wobben" wrote
I have this programm :
tournooi = [{'thuis': 'A','uit': "B",'thuisscore': 20, 'uitscore':
...
for wedstrijd in tournooi :
if wedstrijd['thuis'] in stand :
print "True"
stand is a list of dictionaries so this will never be
> To: tutor@python.org
> From: alan.ga...@btinternet.com
> Date: Fri, 8 Oct 2010 09:02:05 +0100
> Subject: Re: [Tutor] list of dict question
>
>
> "Roelof Wobben" wrote
>
>> I have this programm :
>>
>> tournooi = [{'thuis': 'A','uit': "B",'thuisscore': 2
"Roelof Wobben" wrote
I have this programm :
tournooi = [{'thuis': 'A','uit': "B",'thuisscore': 20, 'uitscore':
15},{'thuis': 'C','uit': "D",'thuisscore': 80, 'uitscore': 40}]
stand = []
tussen_thuis = {}
tussen_uit = {}
Here you create your dictionary objects.
You never create any more d
Hello,
I have this programm :
tournooi = [{'thuis': 'A','uit': "B",'thuisscore': 20, 'uitscore':
15},{'thuis': 'C','uit': "D",'thuisscore': 80, 'uitscore': 40}]
stand = []
tussen_thuis = {}
tussen_uit = {}
for wedstrijd in tournooi :
if wedstrijd['thuis'] in stand :
print "True"
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