(Did not do a reply-all earlier)
On Sat, Oct 10, 2009 at 3:20 PM, xbmuncher wrote:
> Which piece of code will conserve more memory?
> I think that code #2 will because I close the file more often, thus freeing
> more memory by closing it.
> Am I right in this thinking... or does it not save me a
Which piece of code will conserve more memory?
I think that code #2 will because I close the file more often, thus freeing
more memory by closing it.
Am I right in this thinking... or does it not save me any more bytes in
memory by closing the file often?
Sure I realize that in my example it doesn
Thats for all the responses. I'm going to use Kents method. I'll let you
know what I work out.
Rudiger - I did think about that. Luckily I am generating the list with a
start datetime and end datetime so if those don't exist
in either end if the list I can insert them after I check the dates betwee
Ah! but are we sure that the max and min dates are actually in the list?
If there are 'missing dates' it might just be possible that it is the
max or min date that is missing.
On Fri, 09 Oct 2009 16:43 -0400, "Kent Johnson" wrote:
> On Fri, Oct 9, 2009 at 3:16 PM, Glen Zangirolami
> wrote:
> > I
On Fri, Oct 9, 2009 at 3:16 PM, Glen Zangirolami wrote:
> If i have a list of dates:
> date_list =
> ['2008-12-29','2008-12-31','2008-01-01','2008-01-02','2008-01-03','2008-01-05']
> How do I find the missing dates in the range of dates and insert them into
> the list so I get?
> date_list =
> ['2
Glen Zangirolami wrote:
If i have a list of dates:date_list =
['2008-12-29','2008-12-31','2008-01-01','2008-01-02','2008-01-03','2008-01-05']
How do I find the missing dates in the range of dates and insert them into
the list so I get?
date_list =
['2008-12-29','2008-12-30','2008-12-31','2008-01
On Fri, Oct 9, 2009 at 2:16 PM, Glen Zangirolami wrote:
> If i have a list of dates:date_list =
> ['2008-12-29','2008-12-31','2008-01-01','2008-01-02','2008-01-03','2008-01-05']
>
> How do I find the missing dates in the range of dates and insert them into
> the list so I get?
> date_list =
> ['20
If i have a list of dates:date_list =
['2008-12-29','2008-12-31','2008-01-01','2008-01-02','2008-01-03','2008-01-05']
How do I find the missing dates in the range of dates and insert them into
the list so I get?
date_list =
['2008-12-29','2008-12-30','2008-12-31','2008-01-01','2008-01-02','2008-01
On Thu, Oct 8, 2009 at 3:36 PM, Luke Paireepinart
wrote:
> Oops, accidentally replied off-list.
>
> -- Forwarded message --
> From: Luke Paireepinart
> Date: Thu, Oct 8, 2009 at 3:36 PM
> Subject: Re: [Tutor] Troubles with lists and control flow
> To: Eduardo Vieira
>
>
>
>
> On
On Fri, Oct 9, 2009 at 11:02 PM, Kent Johnson wrote:
> On Fri, Oct 9, 2009 at 3:54 AM, Stefan Lesicnik wrote:
>
> You can easily keep track of the previous item by assigning it to a
> variable. For example this shows just the increasing elements of a
> sequence:
>
> In [22]: items = [0, 1, 3, 2,
On Fri, Oct 9, 2009 at 3:54 AM, Stefan Lesicnik wrote:
> Hi,
>
> This feels like a strange issue, so i hope I formulate this so its
> understandable.
>
> I have some objects. Each object has associated values. I am looping
> through these objects, working with a value and printing out the
> value.
On Fri, Oct 9, 2009 at 1:21 AM, wesley chun wrote:
> [generator expressions] are
> "lazy" because you iterate over the values one at a time instead of
> creating the entire list. they are slightly slower but save memory.
I don't think you can make a blanket statement comparing speed of list
comp
On Fri, Oct 9, 2009 at 9:35 PM, Oxymoron wrote:
> Thus, you can muck around with x[i] (current item), and x[i+1] (next
> item), and decide how you want to proceed with the loop. Note the use
> of len(x) - 1 rather than just len(x) to easily prevent an IndexError
> or extra special case logic.
"ea
Hello,
On Fri, Oct 9, 2009 at 6:54 PM, Stefan Lesicnik wrote:
> The issue in this case is that i need to check if the one value
> superseeds the other, and in that case, not print it out. I think the
> problem is that when you are in the loop, you dont know about the
> other object that you haven
2009/10/9 Stefan Lesicnik
Hi,
>
> This feels like a strange issue, so i hope I formulate this so its
> understandable.
>
> I have some objects. Each object has associated values. I am looping
> through these objects, working with a value and printing out the
> value.
> The issue in this case is t
Hi,
This feels like a strange issue, so i hope I formulate this so its
understandable.
I have some objects. Each object has associated values. I am looping
through these objects, working with a value and printing out the
value.
The issue in this case is that i need to check if the one value
super
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