Gregor Lingl schrieb:
Marilyn Davis schrieb:
Hi Tutors,
I'm reviewing GUIs and wondering:
When you pack a component, and you specify fill = BOTH, how is this
different from expand = YES?
Hi Marilyn,
This is a bit tricky and hard to explain, so I recommend playing around
with this little program
Alright, so that was a quick example, but
>return not x % 2
A light dawns.
On Thu, 16 Dec 2004 15:58:38 +0900, Guillermo Fernandez Castellanos
<[EMAIL PROTECTED]> wrote:
> Well...
>
> > I find multiple returns to be rather useful
> > def isOdd(x):
> > if not x % 2: return False
> >
I find multiple returns to be rather useful -
def isOdd(x):
if not x % 2: return False
return True
On Thu, 16 Dec 2004 01:06:58 -0500, Brian van den Broek
<[EMAIL PROTECTED]> wrote:
> [Brian van den Broek]
>
> complicated with:>
>
> >>import datetime
> >>def is_leap_year(year):
> >>'''
[Brian van den Broek]
import datetime
def is_leap_year(year):
'''-> boolean
Returns True or False as year is, or is not, a leap year.
'''
is_leap = True
try:
datetime.date(year, 2, 29)
except ValueError:
is_leap = False
return is_leap
Kent Johnson said unto the
At 09:14 PM 12/15/2004, Tim Peters wrote:
[Brian van den Broek]
> in Marc's check_range thread, I had proposed:
>
> def check_in_range(value):
>
> in_range = False
> if 9 < value < 90:
> in_range = True
> return in_range
>
> and DogWalker suggested the better:
>
> def check_in_r
[Brian van den Broek]
> in Marc's check_range thread, I had proposed:
>
> def check_in_range(value):
>
> in_range = False
> if 9 < value < 90:
> in_range = True
> return in_range
>
> and DogWalker suggested the better:
>
> def check_in_range(value):
> return 9 < value < 90
That did it. Thanks, Max.
On Wednesday, December 15, 2004, at 09:28 PM, Max Noel wrote:
On Dec 16, 2004, at 04:20, Max Noel wrote:
def glass_type(glasstype):
if glasstype == 'Red':
myglass = RedGlassCost()
elif glasstype == 'Blue':
myglass = BlueGla
# --superclass--
class FrameCost:
def __init__(self):
self.width = int(0)
self.length = int(0)
# Calculate cost per square foot
def Cost_per_sqft(self, cost):
return (((self.width) * (self.length) / 144.00) * (cost))
# Calculate cost per linear foot
def Cost_per_ft(self, cost):
r
On Dec 16, 2004, at 04:20, Max Noel wrote:
def glass_type(glasstype):
if glasstype == 'Red':
myglass = RedGlassCost()
elif glasstype == 'Blue':
myglass = BlueGlassCost()
elif glasstype == 'Yellow':
myglass = YellowGlassCost()
On Dec 16, 2004, at 03:56, Marc Gartler wrote:
Hi everybody,
Prior to this chunk of code 'glass' has been chosen from a list of
colors via user input, and I now want to have that choice connect to
one of several possible classes:
def glass_type(glasstype):
if glasstype == 'Red':
On Wed, 15 Dec 2004, Marc Gartler wrote:
> Hi everybody,
>
> Prior to this chunk of code 'glass' has been chosen from a list of
> colors via user input, and I now want to have that choice connect to
> one of several possible classes:
>
> def glass_type(glasstype):
> if glasstype == 'Red'
On Wed, 15 Dec 2004 20:40:40 -0500, R. Alan Monroe
<[EMAIL PROTECTED]> wrote:
> > print "0x%0X" % 12345
>
> > displays
> > 0x3039
>
> > instead of 0x03039
>
>
> >>> "%05x" % (12345,)
> '03039'
>
> >>> "0x%05x" % (12345,)
> '0x03039'
>
> ___
> Tutor
Alan Gauld wrote at 09:25 12/12/2004:
> Are these "numerical approximation methods" pythonically possible?
>
Yes and that's how they are normally found - not necessarily with
Python,
but by applying computer simulations of the equations. Generally you
calculate values in ever decreasing increments
Hi everybody,
Prior to this chunk of code 'glass' has been chosen from a list of
colors via user input, and I now want to have that choice connect to
one of several possible classes:
def glass_type(glasstype):
if glasstype == 'Red':
myglass = RedGlassCost()
elif g
Googling for 'python dbcp' turns up this recipe, is this what you are looking
for?
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/81189
Kent
Rene Bourgoin wrote:
Anyone know where I can download the dbcp module for Python
___
No banners. N
At 06:47 PM 12/15/2004, Tony Cappellini wrote:
I'm trying to get Python to automatically print a leading 0 for hex
numbers, but it only seems to work for for decimal numbers.
Oh? print "%0d" % 12345 gives me 12345 - no leading 0
print "0x%0X" % 12345
displays 0x3039
which it should
instead of 0x030
On Wed, 15 Dec 2004 17:47:58 -0800 (PST), Tony Cappellini
<[EMAIL PROTECTED]> wrote:
>
> I'm trying to get Python to automatically print a leading 0 for hex
> numbers, but it only
> seems to work for for decimal numbers.
>
> print "0x%0X" % 12345
>
> displays
> 0x3039
>
> instead of 0x03039
>
> print "0x%0X" % 12345
> displays
> 0x3039
> instead of 0x03039
>>> "%05x" % (12345,)
'03039'
>>> "0x%05x" % (12345,)
'0x03039'
___
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Just got this reply from [EMAIL PROTECTED] --Dick
Regrettably, we don't currently offer a way to limit your search to a
specific section of a site. We really appreciate your thoughtful feedback,
and we'll keep it in mind as we work to improve Google.
Regards,
The Google Team
Dick Moores wrote at
I'm trying to get Python to automatically print a leading 0 for hex
numbers, but it only
seems to work for for decimal numbers.
print "0x%0X" % 12345
displays
0x3039
instead of 0x03039
The Python docs state
The conversion will be zero padded for numeric values, when a 0 is used as
a flag betw
Brian van den Broek wrote:
I've begun to wonder if I am overlooking a
improvement similar to that in DogWalker's suggestion. As an example of
the sort of thing I have been doing:
import datetime
def is_leap_year(year):
'''-> boolean
Returns True or False as year is, or is not, a leap yea
Anyone know where I can download the dbcp module for Python
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Make My Way your home on the Web - http://www.myway.com
___
Tutor maillist - [EMAIL PROTECTED]
htt
Hi all,
in Marc's check_range thread, I had proposed:
def check_in_range(value):
in_range = False
if 9 < value < 90:
in_range = True
return in_range
and DogWalker suggested the better:
def check_in_range(value):
return 9 < value < 90
As I mentioned, I feel as though I have a
Im sorry to bang on about Python structure, but I do struggle with it,
having in the past got into very bad habits with loads of BASIC where
everything was global, and Forth, and hand coded 8031, 8051, 6502 I
cant get my head round how you guys handle a modern structured language
:-)
(PS
Marilyn Davis schrieb:
Hi Tutors,
I'm reviewing GUIs and wondering:
When you pack a component, and you specify fill = BOTH, how is this
different from expand = YES?
Hi Marilyn,
This is a bit tricky and hard to explain, so I recommend playing around
with this little program from John Grayson's Tki
Hi Tutors,
I'm reviewing GUIs and wondering:
When you pack a component, and you specify fill = BOTH, how is this
different from expand = YES?
Thank you for any insight.
Marilyn Davis
___
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Very elegant, It makes me feel like "I should have thought of that". Thanks
for the help and the reminder to think of the simplistic approach.
John
-Original Message-
From: Tim Peters [mailto:[EMAIL PROTECTED]
Sent: Wednesday, December 15, 2004 12:15
To: Ertl, John
Cc: tutor-list (Pytho
On Wed, 15 Dec 2004, Tim Peters wrote:
> ... return ("%09.4f" % n).replace('.', '')
Totally cool.
Marilyn
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[Ertl, John]
> I need to take a number and turn it into a formatted string.
> The final output needs to look like when the X is the
> integer part padded on the left and Y is the decimal part padded
> on the right.
> I figured I could split the number at "." and then use zfill or
> some
Here's one way:
left, right = str(number).split('.')
output = "%04d%d" % (int(left), int(right)) + (4 - len(right)) * '0'
Maybe someone has a more elegant way.
Hope it helps,
Marilyn Davis
On Wed, 15 Dec 2004, Ertl, John wrote:
> I need to take a number and turn it into a formatted string.
I need to take a number and turn it into a formatted string.
The final output needs to look like when the X is the integer
part padded on the left and Y is the decimal part padded on the right.
I figured I could split the number at "." and then use zfill or something
like this (LEVEL
I agree with Kent's opinion. A boolean statement, like 9>> ( 9 < value ) and ( value < 90 )
, maybe a good sense of boolean type will be made, because 'and'
operation is always associating with boolean.
Juan Shen
在 2004-12-15三的 07:43 -0500，Kent Johnson写道：
> Brian van den Broek
I'll second this -
> In general, Python's flexibility with boolean values is a strength of the
> language and I recommend
> you try to get comfortable with it.
If you come across something, and you're not sure if it'll evaluate
true or false, fire up IDLE or similar intepreter, and test it!
I'
Brian van den Broek wrote:
DogWalker said unto the world upon 2004-12-15 00:32:
"Brian van den Broek" <[EMAIL PROTECTED]> said:
I have a some style suggestions for you, too.
Try it this way:
def check_in_range(value):
in_range = False
if 9 < value < 90:
in_range = True
DogWalker said unto the world upon 2004-12-15 00:32:
"Brian van den Broek" <[EMAIL PROTECTED]> said:
Marc Gartler said unto the world upon 2004-12-14 18:12:
Hi all,
I am fairly new to both Python & programming, and am attempting to
create a function that will test whether some user input is an int
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