t a quick test and it
> definitely seems to work for the examples I've gave.
>
> Thanks again,
>
> Scott
>
>
> From: Nikolas Tautenhahn [via Lucene]
> Sent: Monday, August 23, 2010 3:14 PM
> To: Scottie
> Subject: Re: Tokenising on Each Letter
>
>
> Hi Scotti
Nikolas, thanks a lot for that, I've just gave it a quick test and it
definitely seems to work for the examples I've gave.
Thanks again,
Scott
From: Nikolas Tautenhahn [via Lucene]
Sent: Monday, August 23, 2010 3:14 PM
To: Scottie
Subject: Re: Tokenising on Each Letter
Hi Scottie,
> Could you elaborate about N gram for me, based on my schema?
just a quick reply:
> positionIncrementGap="100">
>
>
>
>
> generateNumberParts="0" catenateWords="1" catenateNumbers="0" catenateAll="0"
> splitOnCaseChange="1" splitOnNumerics="0
Probably a good idea to post the relevant information! I guess I thought it
would be a really obvious answer but it seems its a bit more complex ;)
It seems you may be correct about the catenat
I suspect (though I can't say for sure since you didn't include your
schema definition, both type and actual field def) that your
problem stems from WordDelimiterFilterFactory options. The
default in the schema usually has catenateall=0. In which case
you have the tokens "ads" and "12" but not "ads
