Re: Understanding the DisMax tie parameter

2011-04-22 Thread Otis Gospodnetic
/DisMaxQParserPlugin#tie_.28Tie_breaker.29 > > Tom > > > > -Original Message- > From: Chris Hostetter [mailto:hossman_luc...@fucit.org] > Sent: Thursday, April 14, 2011 5:41 PM > To: solr-user@lucene.apache.org; yo...@lucidimagination.com > Cc: Burto

Re: Understanding the DisMax tie parameter

2011-04-15 Thread Jay Hill
tie_.28Tie_breaker.29 > > Tom > > > > -Original Message- > From: Chris Hostetter [mailto:hossman_luc...@fucit.org] > Sent: Thursday, April 14, 2011 5:41 PM > To: solr-user@lucene.apache.org; yo...@lucidimagination.com > Cc: Burton-West, Tom > Subject: Re: Und

RE: Understanding the DisMax tie parameter

2011-04-15 Thread Burton-West, Tom
: Thursday, April 14, 2011 5:41 PM To: solr-user@lucene.apache.org; yo...@lucidimagination.com Cc: Burton-West, Tom Subject: Re: Understanding the DisMax tie parameter : Perhaps the parameter could have had a better name. It's essentially : max(score of matching clauses) + tie * (sco

Re: Understanding the DisMax tie parameter

2011-04-14 Thread Chris Hostetter
: Perhaps the parameter could have had a better name. It's essentially : max(score of matching clauses) + tie * (score of matching clauses that : are not the max) : : So it can be used and thought of as a tiebreak only in the sense that : if two docs match a clause (with essentially the same sco

Re: Understanding the DisMax tie parameter

2011-04-14 Thread Jay Hill
Dismax works by first selecting the highest scoring sub-query of all the sub-queries that were run. If I want to search on three fields, manu, name and features, I can configure dismax like this: dismax * 0.0* manu name features *:* Now I'll use this query: http

Re: Understanding the DisMax tie parameter

2011-04-14 Thread Yonik Seeley
2011 at 5:04 PM, Burton-West, Tom wrote: > Hello, > > I'm having trouble understanding the relationship of the word "tie" and > "tiebreaker" to the explanation of this parameter on the wiki. > What two (or more things) are in a tie? and how does the number in the range > from 0 to 1 break the ti