you can also try
URL urlo = new URL(url);// ensure that the url has wt=javabin in that
NamedList namedList = new
JavaBinCodec().unmarshal(urlo.openConnection().getInputStream());
QueryResponse response = new QueryResponse(namedList, null);
On Mon, Feb 8, 2010 at 11:49 PM, Jason Rutherglen
wrote
Ahmet, Thanks, though that isn't quite what I was going for, and it's
resolved besides...
On Mon, Feb 8, 2010 at 10:24 AM, Ahmet Arslan wrote:
>> So here's what happens if I pass in a
>> URL with parameters, SolrJ chokes:
>>
>> Exception in thread "main" java.lang.RuntimeException:
>> Invalid ba
> So here's what happens if I pass in a
> URL with parameters, SolrJ chokes:
>
> Exception in thread "main" java.lang.RuntimeException:
> Invalid base
> url for solrj. The base URL must not contain
> parameters:
> http://locahost:8080/solr/main/select?q=video&qt=dismax
You can't pass url with pa
Here's what I did to resolve this:
XMLResponseParser parser = new XMLResponseParser();
URL urlo = new URL(url);
InputStreamReader isr = new
InputStreamReader(urlo.openConnection().getInputStream());
NamedList namedList = parser.processResponse(isr);
QueryResponse response = new QueryResponse(named
So here's what happens if I pass in a URL with parameters, SolrJ chokes:
Exception in thread "main" java.lang.RuntimeException: Invalid base
url for solrj. The base URL must not contain parameters:
http://locahost:8080/solr/main/select?q=video&qt=dismax
at
org.apache.solr.client.solrj.im
Sorry for the poorly worded title... For SOLR-1761 I want to pass in a
URL and parse the query response... However it's non-obvious to me how
to do this using the SolrJ API, hence asking the experts here. :)
