On Fri, 2003-09-05 at 13:12, Patrick Nelson wrote:
> RH9
>
> Have a php page and I want the outcome of
>
> du -hs /var/spool/imap/$username | awk '{print $1}'
>
> however, username is (say) joe.user.example.com but the directory is
> joe^user^example^com
>
> Any sed or awk experts help me do t
However, if you want, here goes the "sed" solution:
du -sh /var/spool/mail/`echo -e $USERNAME | sed 's/\./^/'`
[]`s
Tiago.
--
redhat-list mailing list
unsubscribe mailto:[EMAIL PROTECTED]
https://www.redhat.com/mailman/listinfo/redhat-list
On 09/05/03 11:12 -0700, Patrick Nelson wrote:
> RH9
>
> Have a php page and I want the outcome of
>
> du -hs /var/spool/imap/$username | awk '{print $1}'
>
> however, username is (say) joe.user.example.com but the directory is
> joe^user^example^com
>
> Any sed or awk experts help me do this
> RH9
>
> Have a php page and I want the outcome of
>
> du -hs /var/spool/imap/$username | awk '{print $1}'
>
> however, username is (say) joe.user.example.com but the directory is
> joe^user^example^com
>
> Any sed or awk experts help me do this in one line? The output is
> simply the amount of s
RH9
Have a php page and I want the outcome of
du -hs /var/spool/imap/$username | awk '{print $1}'
however, username is (say) joe.user.example.com but the directory is
joe^user^example^com
Any sed or awk experts help me do this in one line? The output is
simply the amount of space used by the
