On Wed, 12 Feb 2003, Robert P. J. Day wrote:
> that will only detect if a string *starts* with at least one integer.
Exactly. So, unless you're expecting negative numbers, this will prevent
yet another kind of invalid data.
--
"Of course I'm in shape! Round's a shape, isn't it?"
--
redhat-
On Tue, 11 Feb 2003, Todd A. Jacobs wrote:
> That's why constructs like:
>
> [[ 1 < a ]]; echo $?
>
> work. Incidentally, *any* number will evaluate to less than "a" in
> lexicographic sort order, so this can be used as another valid test for
> integers, and will be faster since it doesn't
On Tue, 11 Feb 2003 11:07:16 -0500, Gordon <[EMAIL PROTECTED]> wrote:
>I've searched all over for an answer to this and haven't found one yet!
>
>Is there a way in a bash script to test if a variable contains an
>integer? I want to create a script that uses some simple arithmetic but
>bash bombs
Todd A. Jacobs wrote:
On Tue, 11 Feb 2003, Gordon wrote:
Is there a way in a bash script to test if a variable contains an
integer? I want to create a script that uses some simple arithmetic but
Nope. You'll have to do something more arcane:
function IsInt {
if egrep -q '[[:digit:]]+'
On 13:53 11 Feb 2003, Gordon <[EMAIL PROTECTED]> wrote:
| It's just kind of wierd that the shell has builtin math functions, but
| can't, by itself, tell you if a value is a valid number.
You'll find you can usually contrive not to feed non-numbers to your
operations and don't need such a test of
On 14:07 11 Feb 2003, Robert P. J. Day <[EMAIL PROTECTED]> wrote:
| On Tue, 11 Feb 2003, Gordon wrote:
| and the matching also supports \( \)-style tagging a la Perl,
| so you can get the actual match itself.
More like sed really. Perl doesn't slosh the brackets.
--
Cameron Simpson, DoD#743
On 11:33 11 Feb 2003, Robert P. J. Day <[EMAIL PROTECTED]> wrote:
| On Tue, 11 Feb 2003, Gordon wrote:
| $ man expr
|
| the "expr" utility is, IMNSHO, sadly overlooked.
Forks an extra process. Needlessly slow. Cheers,
--
Cameron Simpson, DoD#743[EMAIL PROTECTED]http://www.zip.com.a
On 16:37 11 Feb 2003, Robert Tinsley <[EMAIL PROTECTED]> wrote:
| On Tue, 2003-02-11 at 16:31, Anthony E. Greene wrote:
| > How about a case statement:
| > case $var in
| >1234567890)
|
| i think you mean
| 1|2|3|4|5|6|7|8|9|0)
Or just:
case $var in
[0-9])
This wor
On Tue, 11 Feb 2003, Gordon wrote:
> It's just kind of wierd that the shell has builtin math functions, but
> can't, by itself, tell you if a value is a valid number.
Not really, since bash variables don't have type. Essentially, all
variables are strings; the fact that you can apply integer logi
On Tue, 11 Feb 2003, Gordon wrote:
> Robert P. J. Day wrote:
> > $ man expr
> >
> > the "expr" utility is, IMNSHO, sadly overlooked.
> >
> > rday
> >
> >
> >
> Thanks for the suggestion. I figured out that I can use
>
> $ expr match $var "[0-9]*$"
>
> and it will return >=1 for a valid i
Robert P. J. Day wrote:
On Tue, 11 Feb 2003, Gordon wrote:
I've searched all over for an answer to this and haven't found one yet!
Is there a way in a bash script to test if a variable contains an
integer? I want to create a script that uses some simple arithmetic but
bash bombs out if you t
On Tue, 11 Feb 2003, Gordon wrote:
> Is there a way in a bash script to test if a variable contains an
> integer? I want to create a script that uses some simple arithmetic but
Nope. You'll have to do something more arcane:
function IsInt {
if egrep -q '[[:digit:]]+' <(echo $1)
On Tue, 2003-02-11 at 16:31, Anthony E. Greene wrote:
> How about a case statement:
>
> case $var in
>1234567890)
i think you mean
1|2|3|4|5|6|7|8|9|0)
> do something;;
>*)
> echo $var is not a number
> esac
cheers,
--
[EMAIL PROTECTED]
[ do NOT use the following e-
On Tue, 11 Feb 2003, Gordon wrote:
> I've searched all over for an answer to this and haven't found one yet!
>
> Is there a way in a bash script to test if a variable contains an
> integer? I want to create a script that uses some simple arithmetic but
> bash bombs out if you try to do a compar
Gordon wrote:
I've searched all over for an answer to this and haven't found one yet!
Is there a way in a bash script to test if a variable contains an
integer? I want to create a script that uses some simple arithmetic but
bash bombs out if you try to do a comparison or arithmetic with a
non-
-BEGIN PGP SIGNED MESSAGE-
> "Gordon" == Gordon <[EMAIL PROTECTED]> writes:
Gordon> I've searched all over for an answer to this and haven't
Gordon> found one yet! Is there a way in a bash script to test if
Gordon> a variable contains an integer? I want to create a scrip
On Tue, 2003-02-11 at 16:07, Gordon wrote:
> I've searched all over for an answer to this and haven't found one yet!
>
> Is there a way in a bash script to test if a variable contains an
> integer? I want to create a script that uses some simple arithmetic but
> bash bombs out if you try to do a
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