>Jon Haugsand wrote:
>> * [EMAIL PROTECTED]
>>
>>>#!/bin/bash
>>>1st_arg=$1
>>
>> number not allowed in front.
>>
>>
>>>prosesses=`lsof -i`
>>>prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
>>
>> Cannot understand this to work in gawk. In any case, you might do
>> this a lot more e
I'm trying to get a pidof a php script by capturing the path:
like /home/somebody/my_script which will be the first arg. to the bash script
Could anybody tell me what's wrong with this script ?
I'm new to scripting in general so any help would be apreciated !
#!/bin/bash
1st_arg=$1
prosesses=`l
