would be grateful for any suggestions on this slight modification.
Otherwise, I can make do with my version.
Thanks,
rcoder
rcoder wrote:
>
> Thank you Ben! This is very clear.
> rcoder
>
>
> Ben Tupper wrote:
>>
>>
>> On Jul 15, 2008, at 5:16 PM, rcoder
#now calculate respective ranges for
data matrix
mm[,n]<-range(mat[,n],na.rm=T) #inserts min/max values into sc
matrix
for (m in 1:nr) {
sc[m,n]<-100*(mat[m,n]-mm[1,n])/(mm[2,n]-mm[1,n]) #re-scaling onto
percentile ranking
}
separate
matrix.
On a separate matter, I have a matrix containing data on which perform a
regresssion over a rolling time period. Is there a convenient way I can do
this for each column, and then save the gradient to an o/p matrix?
Thanks,
rcoder
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Hi Achim,
Thanks for your reply. rollmean and rollmax functions exist, but is there
anything for returning the minima on a rolling basis? I know there is no
rollmin in the zoo library.
Thanks,
rcoder
Achim Zeileis wrote:
>
> On Thu, 24 Jul 2008, rcoder wrote:
>
>> Hi ev
oduct of sequential rows in a preceeding
matrix: i.e. rows 1*2 -> row 1 in o/p matrix; rows2*3-> row 2; rows
4*5->row3 etc.
Thanks,
rcoder
stephen sefick wrote:
>
> how about rollapply in the zoo package?
>
> On Fri, Jul 25, 2008 at 8:37 AM, rcoder <[EMAIL PROTECT
Hi everyone,
I want to perform an operation on a matrx that outputs the product of
successive pairs of rows. For example: calculating the product between rows
1 & 2; 3 & 4; 5 & 6...etc.
Does anyone know of any readily available functions that can do this?
Thanks,
rcoder
-
Hi everyone,
Using the rolling regression function - rollingRegression(formula, data,
width, ...) - is there a way to output only selected coefficients to a
results matrix. For e.g. if I only wanted the slope coefficients to be
recorded, how would I go about doing this?
Thanks,
Michael
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Hi everyone,
Is there a way to perform a rollapply operation on a time series data matrix
and preserve the time frame? Currently, when I apply rollapply in its
standart form, the date column is no longer present in the o/p matrix.
Thanks,
rcoder
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rcoder wrote:
>
> Hi everyone,
>
> Is there a way to perform a rollapply operation on a time series data
> matrix and preserve the time frame? Currently, when I apply rollapply in
> its standart form, the date column is no longer present in the o/p matrix.
>
> Thanks,
complete element pairs
Does anyone know how I can apply a correlation, ignoring any NAs?
Thanks,
rcoder
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Hi Gabor,
Thanks for your reply. Assuming I have a time series that is ready made
(i.e. not constructed it using a zoo function) will the procedure below
still retain the dates in the matrix?
Thanks,
rcoder
quote author="Gabor Grothendieck">
rollapply along an index:
library(
rollapply(), the
columns are not recognised and the regression breaks down. Is there a more
robust way to reference the columns I need, so that I can apply the
regression across the matrix; 'by.column', but every other column?
Thanks,
rcoder
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urceMat)==i]#selecting the correct column in the
matrix in
turn
SourceMat[,i]<-coef(lm(tt~sel_col), na.action=NULL)
}
Thanks,
rcoder
rcoder wrote:
>
> Hi everyone,
>
> I'm having trouble applying the Cor() function to two matrices, both of
>
)==i] #selecting the correct column in the
matrix in turn
SourceMat[,i]<-coef(lm(tt~sel_col), na.action=NULL)
}
Thanks,
rcoder
Gabor Grothendieck wrote:
>
> Read the last line of every message to r-help.
>
> On Tue, Jul 29, 2008 at 6:15 PM, rcoder <
rce matrix:
for (i in 1:10)
{
sel_col<-SourceMat[col(SourceMat)==i] #selecting the correct column
in the matrix in turn
ResultMat[,i]<-coef(lm(tt~sel_col, na.action=NULL))
}
##Code end
I would be grateful for any suggestions to avoid this p
help files and examples. Any suggestions would be grately appreciated.
Many thanks,
rcoder
Gabor Grothendieck wrote:
>
> That's good. Try this:
>
> 1. put set.seed(1) at the top of the code to make it reproducible.
>
> 2. replace body of loop with:
>sel_col<-S
arguments in the parentheses? One way
would be to introduce an if statement, but is this the only way?
Thanks,
rcoder
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matrix into a time series
matrix, I lose the dates in the row.names column. I just want to know if
anyone could suggest a way to get around this problem, i.e. keep the
row.names column in place, and use the rollapply() statement as above.
Thanks,
rcoder
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offset = offset, singular.ok = singular.ok, ...) :
0 (non-NA) cases
Can anyone see what I am doing incorrectly? I hope the example code helps.
Thanks,
rcoder
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t)
for (j in 1:5) #1st nested loop
{
PmatWt[j,]<-Pmult[j,]*mult_col[j,]
}
#rolling regression analysis...
for (k in 1:maxcol) #2nd nested loop
{
sel_col<-PmatWt[,k]
if(!all(is.na(sel_col))) {Preg[,k]<-coef(lm(tt~
Thanks for your reply Gabor.
As I already have a dates column in my dataframe (in column row.names), is
it possible to preserve this whilst still making a data set suitable for
rollapply()?
Thanks,
rcoder
Gabor Grothendieck wrote:
>
> If its regular you can convert it to ts or zoo
Hi,
I guess my question is really more about the nested for loop construct and
whether it is doing what I intend it to do in my code in the previous post.
I would be grateful if anyone who has used nested loops could let me know if
I am doing something wrong.
Thanks,
rcoder
rcoder wrote
k] vs [j:(j+1),k) in the regression statement - forcing successive slope
data to overwrite cell locations containing intercept data.
Also, the full code takes an awfully long time to run. Would anyone be able
to suggest a way for mee to speed it up - perhaps in the regression
algorithm?
Than
, but the titles suggested the acf was
calculated between adjacent columns in the matrix, which is something I was
puzzled about.
Thanks,
rcoder
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Hi Gary,
Thanks for your reply. This works fine. Is there any way to send the ACF
data to a matrix, so I could analyse the data in excel for e.g.?
Thanks,
rcoder
Ling, Gary (Electronic Trading) wrote:
>
> Hi, here is one possible solution ...
> -gary
>
&
lieve there is nothing wrong
with the code. I was just wondering if this is normal program execution
speed for such an operation on a P4 with 2GB RAM?
Thanks,
rcoder
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Sent fro
Hi everyone,
Is there a way to vary the increment size in a for loop? For e.g. when
incrementing in steps greater than unity.
Thanks,
rcoder
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Don't worry, I got it:
for(x in seq(1,100,5)) {
print(x)
}
where the step size is 5.
rcoder
rcoder wrote:
>
> Hi everyone,
>
> Is there a way to vary the increment size in a for loop? For e.g. when
> incrementing in steps greater than unity.
>
> Thanks,
>
something similar to
an !all(is.na() construct)?
Thanks,
rcoder
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__
R-help@r-p
, but the operation
did not fill the results matrix. Coulc anyone offer any advice to assist
with this operation?
Thanks,
rcoder
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le of the
syntax for incorporating an AND in a conditional IF statement.
Thanks,
rcoder
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Dear Henrique,
This is exactly what I need. Thank you very much for your help!
rcoder
Henrique Dallazuanna wrote:
>
> Try this:
>
> x <- data.frame(Dates = seq(as.Date('2008-01-01'),
> as.Date
Thank you all for your replies. This is all very useful information for me!
Ted, thank you very much for the extra explanation and example.
Many thanks,
rcoder
Ted.Harding-2 wrote:
>
> On 13-Aug-08 16:45:27, rcoder wrote:
>> Hi everyone,
>> I'm trying to cre
ror is generated:
Error in if mat[j,k] !=0 { :missing value where TRUE/FALSE needed
I'm not sure how to resolve this.
Thanks,
rcoder
Henrik Bengtsson (max 7Mb) wrote:
>
> FYI,
>
> there is an isZero() in the R.utils package that allows you to specify
> the prec
eros##
for (j in 1:5000)
{
for (k in 1:2000)
{
if(mat[j,k]!=0 & !is.NaN(mat[j,k])) {mat_zeroless[j,k]<-mat[j,k]}
}
}
##Code End
Error in if (mat[j,k] !=0 & !is.NaN(mat[j,k])) { :missing value where
TRUE/FALSE needed
I'm not sure how to resolve this.
rcoder
is
satisfied, but the data rows do not overlap at all.
rcoder wrote:
>
> Hi everyone,
>
> I'm trying to calculate correlation coefficients between corresponding
> columns in two matrices with identical dimensions but different data. The
> problem is that the matrices c
no complete element pairs
Is there something I'm not including in the 'cor' parentheses? I apologise
for not including the true original data frames.
Thanks,
rcoder
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Hi Daniel,
Thanks for your reply. I experimented with various options since my poet and
eventually tried use="pairwise.complete.obs" which seemed to do the trick.
Thanks,
rcoder
Daniel Malter wrote:
>
> Hi,
>
> the argument use should be: use="p" (for pai
Hi Cindy,
Take a look at the following. This should help get you started.
http://www.stat.umn.edu/~charlie/rc/
rcoder
cindy Guo wrote:
>
> Hi, everyone,
>
> I need to use a C library. But since I have little experience in C, I want
> to call this C library in R and progra
location?
Thanks,
rcoder
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https://stat.ethz.ch
you don't have code, at least provide a before/after version of
> the matrix that you would like. It is easy to use indexing to move
> stuff around, we just have to know what is it that you want to move.
>
> On Wed, Jul 9, 2008 at 2:57 PM, rcoder <[EMAIL PROTECTED]> wrote:
>
e?
Thanks,
rcoder
Gabor Grothendieck wrote:
>
> If its a zoo or ts time series you can use the lag function.
>
> On Wed, Jul 9, 2008 at 2:57 PM, rcoder <[EMAIL PROTECTED]> wrote:
>>
>> Hi everyone,
>>
>> I have some data in a matrix, and I want to shift
This is great! Thank you very much Gabor.
rcoder
Gabor Grothendieck wrote:
>
> See ?lag and in zoo ?lag.zoo. Both pages have
> examples. Using lag.zoo here it is with your data:
>
> Lines <- "Date Apples Oranges Pears
> 1/7 2 3
Hi everyone,
I want to score a set of data (-ve to +ve) using a 0-10 scale. I have the
data in an R matrix, so I need to add another column, containing the scores
and resave.
I would be grateful for suggestions on how best to do this.
Thanks,
rcoder
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Hi everyone,
I want to score a set of data (-ve to +ve) using a 0-10 scale. I have the
data in an R matrix, so I need to add another column, containing the scores
and resave.
I would be grateful for suggestions on how best to do this.
Thanks,
rcoder
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,
rcoder
Ben Tupper wrote:
>
>
> On Jul 15, 2008, at 8:16 AM, rcoder wrote:
>
>>
>> Hi everyone,
>>
>> I want to score a set of data (-ve to +ve) using a 0-10 scale. I
>> have the
>> data in an R matrix, so I need to add another column, containing
Thank you Ben! This is very clear.
rcoder
Ben Tupper wrote:
>
>
> On Jul 15, 2008, at 5:16 PM, rcoder wrote:
>
>>
>> Hi Ben,
>> Yes, this is more or less what I want to do. I want to apply this
>> data in
>> columns in a matrix, and insert the re
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