(8) - daemon to execute scheduled commands (Vixie Cron)
So you schedule your task.
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PLEA
tc..) and the row id itself (so
consider pass
the left hand of assignment entirely). I would use:
fmean <- function(row, col_selection) { # homework for you here }
Best Regards,
--
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gt; > to programming in R. I see no future in this enterprise.
>
>
>
> *Gotta* be a fortune!!!
>
> cheers,
>
> Rolf
>
Jim++
Rolf++
must be.
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y for this long post
marco
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oes not solve the problem: same message.
So: this is the blind alley.
thanks for any feedback
marco
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Hi everyone,
have a small problem trying to converting a dataset in matrix form to an
array.
Specifically: data include 3D measurement -x,y,z of 59 points in 36 objects.
They are stored as a matrix (x) of 2124 rows and 3 columns.
What I want to do is to extract each subject's dataset using an arra
7-15"
[14,] "2011-07-16"
[15,] "2011-07-17"
[16,] "2011-07-18"
[17,] "2011-07-19"
[18,] "2011-07-20"
[19,] "2011-07-21"
[20,] "2011-07-22"
[21,] NA
[22,] NA
[23,] NA
7-15"
[14,] "2011-07-16"
[15,] "2011-07-17"
[16,] "2011-07-18"
[17,] "2011-07-19"
[18,] "2011-07-20"
[19,] "2011-07-21"
[20,] "2011-07-22"
[21,] NA
[22,] NA
[23,] NA
Hi everyone
just a brief question:
I'm trying to perform a smallest space analysis on nonmetric variables with
R.
It seems there are at lear a couple of packages to perform non metric MDS
but still not found any info concerning SSA.
Any clue?
thanks in adv.
Marco
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n the map, I would like to have a
"smoothed" scatterplot of the same superimposed on the map. Tried with the
smoothScatter function, but really have no idea how to combine the map with
the resulting graph.
tx in adv
marco
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thanks a lot!!
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Hi everyone
I'm here with a brief question:
Does anyone have some idea on how to perform Smallest Space Analysis in R?
I'm aware of several packages/methods for non metric multidimensional
scaling, but no clue about this specific technique.
Thanks for any feedback
Marco
--
View th
arry out cross-validations. The vignette
'Introduction to the package' provides an introduction, the vignette 'Math
details' provides mathematical background.
Version 1.2.1 is now available. Please send bugs, requests and comments to the
package maintainer.
Regards,
distributions from the
data or 2) use posterior estimates for the parameters.
Cheers,
Marco
On 13 July 2017 at 06:29, Ross Chapman wrote:
> Hi all
>
>
>
> I have built a Bayesian network using discrete data using the bnlearn
> package.
>
>
>
> When I try to run the cp
din your system, or it is not correctly configured to be
> used from QGIS
> Click here to know more about how to install and configure R to be
> used with QGIS"
>
> [[alternative HTML version deleted]]
>
Maybe you should ask in a QGIS forum, your QGIS question. But, j
rvals in the evidence.
Cheers,
Marco
--
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Lecturer in Statistics, Department of Statistics
University of Oxford, United Kingdom
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that these classes should both typically
> return a value for ABW that is very much higher than the threshold value.
That may be, but much depends on the specific sample the model was
fitted from. How does the fitted network look like?
Cheers,
Marco
--
Marco Scutari, Ph.D.
L
7;y', TR = c(9,
max(data$TR)), BU = c(15819, max(data$BU)), RF = c(2989,
max(data$RF)), n=10^6, method = "lw")
3) look at the parameters in your fitted network and diagnose why this
is happening.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department
t;"character""character"
op rain t t2 ts_
"character""character""character""character""character"
And I noticed everything is type "cha
an average of ~= 13 without considering
FFB. If I assume FFB is positive, then I can easily see E(y) ~= 15 and
E(y) - 1.96 * 0.96 s.d. ~= 13.5. So ABW < 11 has zero or almost zero
probability mass.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department of Statistic
s for
deletion of the role pattern space, so if you are trying to substitute
use:
s/pattern//g # effectively removing pattern from the text
Best Luck,
Marco
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ite
where it is explicitly reported to be "confidential"), so I have to
review a bit of likelihood theory along with some implementation
details.
In the meantime, I wonder if anyone here could point out any related
documentation to me.
Thank you.
Marco.
__
I suspect that your "treatment" levels are perfectly nested inside the
"soilgroup" levels. If this were the case you can either use one of the
factor in your analysis or the other, depending on what you want to
analyze.
Il giorno Wed, 11 Feb 2015 14:47:18 +
Mir Salam ha scritto:
> Dear all,
Thank you very much, Ben. Your answer has been very useful.
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and
standard regression and Theil-Sen regression are practically
identical. But the Siegel regression seems to have a bias that I cannot
understand. May I ask for a possible explanation? The bias may be related
to the number of ties in the set of data? Here's the code and the image.
Best regards.
M
that we haven’t overlooked
> something more basic, is that such
> high breakdown estimates sacrifice some efficiency, that is to say, they
> are more variable than other methods
> when the data is well behaved, and of course, the Galton data is famously
> “almost Gaussian”.
>
> On Feb
cex=1, number=3, columns=3, col="black", pch=16, overlap = 0.1,
panel=function(x,y,...) {
points(x,y,pch=16)
panel.smooth(x,y,span=.8,iter=5,...)
abline(lm(y ~ x), col="blue")} )
Thank you.
Marco
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e(text="(M=='s')")),
evidence=list(lag1.M1='s'),
method = "lw")
passing str2 as a list.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department of S
ot;method")= chr "lw"
To compute P(A = a | whatever you conditioned on), just sum the
corresponding weights over the total weight mass. Since no language
trickery is involved, this works reliably.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department of Sta
Hello folks,
I have a couple of issues with the metafor package, specifically with
the forest graphs.
I am currently conducting a Meta-Analysis in economics throughout the
metafor package.
My meta-analysis has the specific of having different cases from
single studies, and this proven to be chall
ce and your time, and many
compliments for the package, is guiding me through the use of R for
the first time - as you might have guessed.
Marco
On 24 August 2015 at 16:50, Viechtbauer Wolfgang (STAT)
wrote:
> I cannot reproduce the issue with 'ilab' not being shown when using '
ssage-
>> From: Michael Dewey [mailto:li...@dewey.myzen.co.uk]
>> Sent: Tuesday, August 25, 2015 13:23
>> To: Marco Colagrossi; Viechtbauer Wolfgang (STAT)
>> Cc: r-help@r-project.org
>> Subject: Re: [R] Metafor and forest(); not showing 'ilab' and text
&
e there the formulas for it somewhere? So far I
only found the formulas for the estimators included in the metafor
package.
3. metareg1 <- rma.mv(pc, var, random = ~ 1 | author, mods = ~ pub +
SIMiv, data=codebook)
Again, if I'm correct this should be a multilevel meta regression
(correct me
The solution that you proposed works perfectly, thank you very much.
I'll wait for Wolfgang answer as I'm having few doubts about the models.
Thanks
On 31 August 2015 at 18:34, Michael Dewey wrote:
> Comments in line
>
> On 31/08/2015 16:08, Marco Colagrossi wrote:
>>
and correct that with struct="HAR" ?
Sorry for the long mail, I wanted to explain as better as possible,
and thank you again for your help, It is incredibly appreciated.
Marco
On 31 August 2015 at 19:28, Viechtbauer Wolfgang (STAT)
wrote:
> Have you read help(rma.mv)? It describes i
Is there a function in R to get the set of all unit vectors which are
orthogonal to a given vector?
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Ok, thanks!
On 2015-10-29 09:03 PM, Duncan Murdoch wrote:
On 29/10/2015 6:38 PM, Marco Inacio wrote:
Is there a function in R to get the set of all unit vectors which are
orthogonal to a given vector?
No.
Duncan Murdoch
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I think that's just what I needed. Thanks!
On 2015-10-29 09:55 PM, peter dalgaard wrote:
On 30 Oct 2015, at 00:03 , Duncan Murdoch wrote:
On 29/10/2015 6:38 PM, Marco Inacio wrote:
Is there a function in R to get the set of all unit vectors which are
orthogonal to a given vector
als first.
Cheers,
Marco
--
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Lecturer in Statistics, Department of Statistics
University of Oxford, United Kingdom
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PLEAS
produce a graph + barplots plot from
Rgraphviz. I have never managed to make it work, though.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department of Statistics
University of Oxford, United Kingdom
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aining?
TAN does not do any sort of feature selection, so all the nodes should
be there. As for "showing the network after training", what kind of
plot are you looking for?
Cheers,
Marco
--
Marco Scutari, Ph.D.
Lecturer in Statistics, Department of S
Hi R'ers,
I noted that R breaks lines for any output greater than 80 chars,
Is there a way to expand this limit ?
Thks
--
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https://stat.et
> 4700 Keele StreetWeb:http://www.datavis.ca
> Toronto, ONT M3J 1P3 CANADA
>
>
# what is missing to you
?gsub
# aliasing
df <- sp.tab[, wanted]
# convert to double
as.double( # convert to double
gsub(',', '.',
ve to upgrade to use it.
Cheers,
Marco
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Lecturer in Statistics, Department of Statistics
University of Oxford, United Kingdom
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|
--
-
|
7.01% | 78
|
-
Marco
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PLEASE do read the
Hi,
the chisq value for .05 level of signif. and 3 DF is 7.81 (one-sided).
Is there a way to calculated it in R (giving level of signif. and DF)?
Marco
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PLEASE do read the
t(paste(expression(paste("R"^2)),round(marco2[1,i],digits=3)," N° of
proteins:",marco3[i]),side=4,cex=.6)
the output is:
paste("R"^2)
Thank you in advance
Marco
/
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joint all the vectors into a
unique data frame (xcan in the usage of hier.part) ?
I´ve been trying to run it, but i keep getting different errors.
Thanks in advance,
Marco
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one please give me some
clues on what that is?
Thanks in advance
Marco
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Hi,
my name is Marco Bressan i'm working to improve ADati package. I study
psicology ad Padua University (Italy). I have this problem: why bartlett.test
function running good and my anova.welch function no?
Ciao,
il mio nome è Marco Bressan e sto lavorando per migliorare il pacchetto
(x)
return(list(p.value=tTest$p.value,t.stat=tTest$stat))
}
Using an lapply statement, as in:
myResults <- lapply(aList, myFnc)
The goal would be to report on the progress of the lapply() function during
processing.
Any suggestion would be greatly appreciated.
Thanks
Marco
--
Marco
<- cbind(date, hcrime)
I have following questions:
a) how can I find out the weeks of every date
b) aggregate the dates falling in the same week
c) sum up the different crimes per week
for better understanding here is an example for a) and b):
dateweek
27-08-2005
control if the result of the apply is correct.
Do anyone find a solution to this issue?
thanks
Marco
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PLEASE do read the posting
Hi,
why the list of "Available CRAN Packages By Date of Publication" is stopped
at 2022-12-25 ?
Regards
Marco Scazzocchio
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t=50)#library(cluster)windows()clusplot(z,
fit$cluster, labels=3, lines=0, cex=0.6, col.txt="black",
col.p="black")#library(factoextra)windows()fviz_cluster(fit, data=z)#*
Thanks if someone has a suggestion!
----
Hi,
I'm working with environmental data which are left-censored and I found the
R package NADA which seems to do the job.
After fitting a complete model, using the cenreg function,I'd like to do a
stepwise procedure to minimize the AIC using the stepAIC function.
Unfortunately, after fitting the m
I'm running Rx64 3.01 on Windows 7 and until the other day I could easily
unzip zip files with unzip (package utils 3.01). Since yesterday however I
get an error. Let's say my zipfile file path is called zfile (I'm omitting
the output directory for this example). When I try to unzip it I get the
fo
tried using only Imports: as suggested by Chambers
but it breaks. Using Depends does not help.
Am I having clashing namespace? Here is my Depends: (or Imports:) line:
Depends: Rsamtools, GenomicFeatures, parallel, rtracklayer, edgeR
Am I simply missing something?
Thanks
-- Marco Blanchette,
mmetric matrix, where raws and colums
are artists and value I get 1 (or true) if they had an exhibition in
the same and in the same place.
My unelegant code is working, but for 96000 observation is requiring
months and months. Gerrit is very elegant, but i run out of memory...
the problem is t
are > 0, wascores) && any(comm < 0))
{ : missing value where TRUE/FALSE needed*
*In addition: Warning message:*
*In Ops.factor(left, right) : < not meaningful for factor"*
Do you think Principal coordinate analysis on a binary distance matrix is a
decent strategy?
Thanks
different network every time it is run on
> the same data set?
This is not surprising, because mmhc() does not have a "start"
argument, so it's starting from the same network over and over. There
is no way to provide a random seed to mmhc(), so the only way
to reassemble observed and predicted class labels and compute your
metrics.
> I also tried the *e1071* package, but I could not find a way to do
> cross-validation.
You might be able to trick the tune() function to do it, but I am not sure.
Marco
--
Marco Scutari, Ph.D.
Research Assoc
~dnum+snum, weights=~pw, data=apiclus2)
a<-svyglm(sch.wide~1, design=dclus2,family=quasibinomial()) #Null model
c<-svyglm(sch.wide~ell*meals, design=dclus2,family=quasibinomial())
anova(a,c)
Many thanks for your help
Marco
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ealt with a similar task and found a solution?
Thank you very much in advance for any help.
Marco
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PLEASE do read the posting
available on
https://r-forge.r-project.org/R/?group_id=1396 prior to submission to CRAN.
--
Marco Geraci PhD CStat
Lecturer in Biostatistics
Institute of Child Health, University College London
London WC1N 1EH, UK
Web: http://marcogeraci.wordpress.com
[[alternative HTML version deleted
ne of the BN classifiers in bnlearn,
naive.bayes()/tree.bayes(), which handle the concept of a response
variable more naturally than general-purpose BNs.
Hope it helps,
Marco
--
Marco Scutari, Ph.D.
Research Associate, Genetics Institute (UGI)
University C
Tcl/Tk and XQuark as recommended.
Ive also tried uninstalling R, reinstalling the latest version (2.15.1 signed)
and all packages, and following the same official steps again. It didnt work
neither.
Could you please help me? R Commander always worked fine on my iMac, until I
updated to Mountain Lion.
that the dataset includes relatively few points. Therefore, I
would also like to interpolate the values for the uncovered geographical
areas.
Thanks in advance for any feedback,
best
marco
[[alternative HTML version deleted]]
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what I have to write in place of "y" in the last loop in order
to refer to xx1, xx2 or xx3?? I want to write something like:
for (i in 1:3) {
xxi<-1}
Thank you for any advice.
Marco
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https
owever, you can
estimate the CPTs from incomplete data using table() and prop.table()
and assemble them in a fitted BN with custom.fit(). On the other hand,
maybe it would be better to write an EM wrapper around bn.fit() to
make the best of the dependence structure of the data?
Cheers,
o solve the problem or to
understand it.
Thank you
Marco.
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my version), and this is why I put time.inc=1 in the
previous call (This other issue is still present in 3.0.2)
I'm going to upgrade my R and check that this little error is actually gone.
Thank you
Marco
2014-07-03 0:17 GMT+02:00 Frank Harrell :
> Please try hard to cr
Hi, Lars.
I don't understand well your question. why don't you simply type
pred_leuk
Call: survfit(formula = leuk.cox, newdata = leuk_new)
records n.max n.start events median 0.95LCL 0.95UCL
1 4242 42 30 1 1 23
2 4242 42 30 7
or in if (history[2, 3] < (history[1, 3] + 1)) theta <-
mean(history[1:2, :
missing value where TRUE/FALSE needed
Does anyone have an idea on how to debug?
Yours sincerely,
Marco
[[alternative HTML version deleted]]
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1 1 0 1 0 0 0 case12 0 0 0 1 1 0 1 1 0 1
0 0 0 .
So, my questions are the following: Is the Jaccard index a good strategy
for my kind of data? Is binary distance used in pvclust is theoretically
more correct? Is there any alternative to pvclust for testing the
significance of my clusters?
Tha
Hello all, can help clarify something?
According to R's lm() doc:
Non-NULL weights can be used to indicate that different observations
have different variances (with the values in weights being inversely
*proportional* to the variances); or equivalently, when the elements
of weights are positiv
Thanks for the answers.
Dear Marco and Goran,
Perhaps the documentation could be clearer, but it is after all a brief help
page. Using weights of 2 to lm() is *not* equivalent to entering the
observation twice. The weights are variance weights, not case weights.
According to your post here
I think we can blame Tim Hesterberg for the confusion:
He writes
"
I'll add:
* inverse-variance weights, where var(y for observation) = 1/weight (as
opposed to just being inversely proportional to the weight) *
"
And, although I'm not a native English speaker, I think there's a spurious
c
No, you are perfectly fine using WLS. The constant of proportionality is the
estimated error variance, i.e., the square of the residual standard error
(as I think I said earlier).
John
You're right. That was a little hard for me to grasp. Thanks for the
patience.
Hi, is it possible to add exposures to a glm with family=binomial()?
It's easy to do it for a Poisson/negative binomial: just multiply the
mean by the exposure, that is, offset(log(exposure)): but this obviously
wrong for a binomial/Bernoulli since the mean must be no bigger than 1.
My goal w
me to bother
at all.
I'm not asking for prepackaged solutions, rather for help in
documentation seeking and links to useful documentation or other
threads (for example: is it worthwhile using parallel computing?)
Thank you to anyone for reading this email.
Marco Barbàra.
P.S.: I work on a Debia
ataset, but I can no
longer find it. Does anybody know where I can find the dataset?
Thanks,
Marco
--
*****
Marco Bee
University of Trento - Department of Economics and Management
via Inama, 5 - 38122 Trento, Italy
Phone: +39-0461-282296, Fa
do so I suggest you should install the
latest bugfix snapshot from bnlearn.com to avoid a few other bugs in
cpquery(..., method = "lw").
Cheers,
Marco
--
Marco Scutari, Ph.D.
Research Associate, Genetics Institute (UGI)
University College London (UCL), United Kingdom
__
is easier to use in a
programmatic way, but it is much more limited in the events you can
use for conditioning. Logic sampling (method = "ls") accepts an
arbitrary R expression as a conditioning event; likelihood weighting
at the moment accepts only a single instantiation of the conditionin
lihood weighting method will work.
> Don't
> hesitate to correct me if I'm wrong.
>From your description, likelihood weighting should be fine.
Cheers,
Marco
--
Marco Scutari, Ph.D.
Research Associate, Genetics Institute (UGI)
University College London (UCL), United Ki
ot;,index=c("Aktie","Datum"),gmm.inst=~PB,lag.gmm=list(c(2,12)),transformation="ld")
Fehler in FUN(X[[1L]], ...) : Indizierung außerhalb der Grenzen
dim(panel)
[1] 3408637
Best regards, Marco
--
GRATIS für alle GMX-Mitglieder: Die maxdome Movie-FLAT!
___
DeaR experts,
I was asked for a log-rank pairwise survival comparison. I've a straightforward
way
to do this using the SAS system:
http://support.sas.com/documentation/cdl/en/statug/63033/HTML/default/viewer.htm#/documentation/cdl/en/statug/63033/HTML/default/statug_lifetest_sect019.htm
What
On Fri, Dec 24, 2010 at 12:01 AM, Michael Bedward
wrote:
> Hello Walt,
>
> Have a look at the bnlearn and deal packages.
>
> Michael
Dear Walt,
take a look also to the catnet/mugnet and pcalg packages,
and if you have questions about bnlearn feel free to ask.
Regards,
Ma
Thank you very much.
Despite prof. Harrell's support (for whom I feel great
esteem) I still remain doubtful about this feature.
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Il giorno Mon, 2 May 2011 07:30:10 -0700 (PDT)
Frank Harrell ha scritto:
> Please elaborate.
It is simply that, generally speaking, i don't like adding numbers to a
plot. I eventually realized that riskset cardinality may be a useful
indication. However, do not discriminate between events and ce
Hi to everybody
I have an array with dimensions 2,4,3,3.
Wanting to sum the matrices in the first two dimensions, I'm trying to use
the "apply" function, but with no results. Have to say I'm quite new with R
syntax.
tx in advance
marco
[[alternative
doing
such dangerous things?
Thanks, Marco.
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and provide commented, minimal, self-contained, re
Thanks a lot for your hint
marco
2011/5/27 Erich Neuwirth
> > arr<-1:72
> > dim(arr)<-c(2,4,3,3)
> > apply(arr,1:2,sum)
> [,1] [,2] [,3] [,4]
> [1,] 297 315 333 351
> [2,] 306 324 342 360
> > apply(arr,3:4,sum)
> [,1] [,2] [,3]
> [
Thanks a lot for your help
marco
2011/5/27 Thomas Lumley
> On Fri, May 27, 2011 at 10:06 AM, marco milella wrote:
> > Hi to everybody
> > I have an array with dimensions 2,4,3,3.
> > Wanting to sum the matrices in the first two dimensions, I'm trying to
> use
>
> Is this result reliable?
No. chisq.test is a non parametric goodness-of-fit test for
*counts*. In my opinion you need a one sample t.test.
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Il giorno Wed, 19 May 2010 08:46:06 -0700 (PDT)
Javier ha scritto:
>
> Dear users,
>
> Is there anyone how knows how to plot the sample size on top of the
> bars of a barchart plot?
Do you mean something like this?
mp <- barplot( VADeaths[1,], ylim = c( 0 , 18 ) )
text( mp , VADeaths[1,] + 0
this is self-reply only to insert my real name
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and provide commented, minimal, self-contained,
eed time interaction...
>
> The cox.zph function is primarily graphical; I would respond to your
> question with "is it good to look at scatterplots before fitting a
> linear model?" My answer to this is emphatically yes.
>
> Terry Therneau
>
>
Thank y
t this is generally
not recommended, isn't it?
Any sort of comment will be appreciated.
Thank you very much.
Marco Barbàra.
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Hi
does anyone know if there is any R function that preforms partial
correlations analysis for censored data?
I found a fortran program on the PSU website at
http://www2.astro.psu.edu/statcodes/cens_tau.f
but I was wondering if there is anything like that in any R package.
Thanks
m.
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